Make sure to show the correct work and solution:   Suppose P(X = 0, Y = 0) = 1/3, P(X = 0, Y = 3) = 1/3, and P(X = 6, Y = 3) = 1/3. Find Cov(X, Y ) and the correlation ρ of X and Y .

A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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Make sure to show the correct work and solution:

 

Suppose P(X = 0, Y = 0) = 1/3, P(X = 0, Y = 3) = 1/3, and P(X = 6, Y = 3) = 1/3. Find Cov(X, Y ) and the correlation ρ of X and Y .

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Follow-up Question

For the first image isn't it supposed to be X = 0? For the second image, what does E(Y) equal to? 

FOLLOW-UP
QUESTIONS
Isn't it
equal to
→
Step 1:-
We can create the probability distribution table for the given information.
P(X,Y)
X=0
X=6
Y=0
1/3
1/3
2/3
Y=3
Total
Step 2
E(XY)= EX*Y*P(X,Y)
= 0*0* (1/3) +0*6*0 +3*0*(1/3) +3*6*(1/3)
= 0+0+0+6
F(XY)= 6
0. (1- sum of all the
probabilities)
1/3
1/3
Total
1/3
2/3
1
Transcribed Image Text:FOLLOW-UP QUESTIONS Isn't it equal to → Step 1:- We can create the probability distribution table for the given information. P(X,Y) X=0 X=6 Y=0 1/3 1/3 2/3 Y=3 Total Step 2 E(XY)= EX*Y*P(X,Y) = 0*0* (1/3) +0*6*0 +3*0*(1/3) +3*6*(1/3) = 0+0+0+6 F(XY)= 6 0. (1- sum of all the probabilities) 1/3 1/3 Total 1/3 2/3 1
FOLLOW-UP
QUESTIONS
Step 3
E(X)= EX*P(X)
=2
E(Y)=ZY*P(Y)
Covariance of X and Y,
Cov(X,Y)= E(XY)-E(X)*E(Y)
= 6-2*2
= 2
Cov(X,Y)= 2
Transcribed Image Text:FOLLOW-UP QUESTIONS Step 3 E(X)= EX*P(X) =2 E(Y)=ZY*P(Y) Covariance of X and Y, Cov(X,Y)= E(XY)-E(X)*E(Y) = 6-2*2 = 2 Cov(X,Y)= 2
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