OH но- но. -H он sugar X он gar X a reducing or a non-reducing sugar? Reducing, because one/both of the rings can open to expose a free aldehyde group Non-reducing, because one/both of the rings can open to expose a free aldehyde group Reducing, because neither of the rings can open to expose a free aldehyde group Non-reducing, because neither of the rings can open to expose a free aldehyde group Reducing, because one/both of the rings can open to expose a free ketone group Non-reducing, because one/both of the rings can open to expose a free ketone group Reducing, because neither of the rings can open to expose a free ketone group Non-reducing, because neither of the rings can open to expose a free ketone group Cannot be determined from the structure shown

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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Consider the structure of sugar X.
H OH
HO
OH
но.
он
Но
OH
sugar X
Is sugar Xa reducing or a non-reducing sugar?
O Reducing, because one/both of the rings can open to expose a free aldehyde group
O Non-reducing, because one/both of the rings can open to expose a free aldehyde group
O Reducing, because neither of the rings can open to expose a free aldehyde group
O Non-reducing, because neither of the rings can open to expose a free aldehyde group
O Reducing, because one/both of the rings can open to expose a free ketone group
O Non-reducing, because one/both of the rings can open to expose a free ketone group
O Reducing, because neither of the rings can open to expose a free ketone group
O Non-reducing, because neither of the rings can open to expose a free ketone group
O Cannot be determined from the structure shown
Transcribed Image Text:Consider the structure of sugar X. H OH HO OH но. он Но OH sugar X Is sugar Xa reducing or a non-reducing sugar? O Reducing, because one/both of the rings can open to expose a free aldehyde group O Non-reducing, because one/both of the rings can open to expose a free aldehyde group O Reducing, because neither of the rings can open to expose a free aldehyde group O Non-reducing, because neither of the rings can open to expose a free aldehyde group O Reducing, because one/both of the rings can open to expose a free ketone group O Non-reducing, because one/both of the rings can open to expose a free ketone group O Reducing, because neither of the rings can open to expose a free ketone group O Non-reducing, because neither of the rings can open to expose a free ketone group O Cannot be determined from the structure shown
Expert Solution
Step 1

Reducing sugars are those which can gives positive Tollen's and fehling's solution test. It means structure must have free aldehyde group . 

Structure in the hemiacetal form can switch to free aldehyde form by ring opening . But structures in acetal form cannot switch to free aldehyde form .

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