OH 1. Hg(OAc)2, H2O 2. NaBH4 CH3 .CH3 H3C Acid-catalyzed addition of water to an alkene yields an alcohol with Markovnikov regiochemistry. The electrophilic H* adds to the sp? carbon with the most hydrogens to yield the most stable carbocation intermediate, which then adds water to give the product alcohol. Because a carbocation intermediate is formed, rearrangements can occur prior to the addition of water. To avoid the possibility of rearrangement and still give a Markovnikov alcohol, alkenes can instead be treated with mercury(II) acetate in aqueous THF and then subsequently reduced with sodium borohydride. This reaction proceeds through a cyclic mercurinium ion intermediate which cannot rearrange. Water adds to the cyclic intermediate at the most substituted carbon to give an organomercury alcohol. The reduction step with sodium borohydride is complex and involves radicals. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions AcO-Hg-OAc AcO-Hg OAC

Chemistry
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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OH
1. Hg(OAc)2, H2O
2. NaBH4
.CH3
.CH3
H2C
H3C°
Acid-catalyzed addition of water to an alkene yields an alcohol with Markovnikov regiochemistry. The electrophilic H* adds to the sp2 carbon with the most hydrogens to yield the most stable
carbocation intermediate, which then adds water to give the product alcohol. Because a carbocation intermediate is formed, rearrangements can occur prior to the addition of water.
To avoid the possibility of rearrangement and still give a Markovnikov alcohol, alkenes can instead be treated with mercury(II) acetate in aqueous THF and then subsequently reduced with sodium
borohydride. This reaction proceeds through a cyclic mercurinium ion intermediate which cannot rearrange. Water adds to the cyclic intermediate at the most substituted carbon to give an
organomercury alcohol. The reduction step with sodium borohydride is complex and involves radicals.
Draw curved arrows to show the movement of electrons in this step of the mechanism.
Arrow-pushing Instructions
AcO-Hg-OAc
AcO-Hg
OAC
Transcribed Image Text:OH 1. Hg(OAc)2, H2O 2. NaBH4 .CH3 .CH3 H2C H3C° Acid-catalyzed addition of water to an alkene yields an alcohol with Markovnikov regiochemistry. The electrophilic H* adds to the sp2 carbon with the most hydrogens to yield the most stable carbocation intermediate, which then adds water to give the product alcohol. Because a carbocation intermediate is formed, rearrangements can occur prior to the addition of water. To avoid the possibility of rearrangement and still give a Markovnikov alcohol, alkenes can instead be treated with mercury(II) acetate in aqueous THF and then subsequently reduced with sodium borohydride. This reaction proceeds through a cyclic mercurinium ion intermediate which cannot rearrange. Water adds to the cyclic intermediate at the most substituted carbon to give an organomercury alcohol. The reduction step with sodium borohydride is complex and involves radicals. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions AcO-Hg-OAc AcO-Hg OAC
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