of the oscillator to occupy the third ener
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A: Given: mass, m=76.2 kg Time period T=1.34 s distance, x=6.17 cm


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- You have a two-wheel trailer that you pull behind your ATV. Two children with a combined mass of 76.2 kg hop on board for a ride through the woods and the springs (one for each wheel) each compress by 6.17 cm. When you pull the trailer over a tree root in the trail, it oscillates with a period of 1.34 s. Determine the following. (a) force constant of the springs (b) mass of the trailerA simple harmonic oscillator's velocity is given by; vy(t) = (0.710 m/s)sin(11.6t − 5.35). Find the oscillator's position, velocity, and acceleration at each of the following times. (Include the sign of the value in your answer.) a) t = 0 sec b) t = 0.5 sec c) t = 2 secIf the frequency of the motion of a simple harmonic oscillator is increased by a factor of 4, by what factor does the maximum speed of the oscillator change? 1/4 O It does not change. 04 02 O 1/2
- You have a two-wheel trailer that you pull behind your ATV. Two children with a combined mass of 74.2 kg hop on board for a ride through the woods and the springs (one for each wheel) each compress by 6.17 cm. When you pull the trailer over a tree root in the trail, it oscillates with a period of 2.04 s. Determine the following. (a) force constant of the springs N/m (b) mass of the trailer kg (c) frequency of the oscillation Hz (d) time it takes for the trailer to bounce up and down 10 timesAn oscillator with a natural frequency of 380 Hz is driven by a 790 Hz sinusoidal signal. At what frequency does it oscillate?* 53. (II) A meter stick is hung at its center from a thin wire (Fig. 14-35a). It is twisted and oscillates with a period of 5.0 s. The meter stick is sawed off to a length of 70.0 cm. This piece is again balanced at its center and set in oscillation (Fig. 14-35b). With what period does it oscillate? yaits istugrs (a) 82 (b)
- A mass of 1.42 Kg is connected to a spring of spring constant 8.71 N/m. An oscillation is started by pulling the mass to the right to amplitude 0.522 m before release and the oscillator moves in air. The oscillation decays to 18.2% of the original amplitude in 58.2 seconds. A=0.241m at 26.38 seconds. b=8.31*10^-2 kg/s. Energy lost = 1.15J a. What would the position of the oscillation be 26.38 seconds after release?In an engine, a piston oscillates with simple harmonic motion so that its position varies according to the expression, x = 6.00 cos (3t + *) where x is in centimeters and t is in seconds. (a) At t = 0, find the position of the piston. What is effect of the phase constant, x/6, in the expression for x(t)? cm (b) At t = 0, find velocity of the piston. How do you find the velocity v(t) of an object if you know the position as a function of time, x(t)? cm/s (c) At t = 0, find acceleration of the piston. | cm/s² (d) Find the period and amplitude of the motion. period amplitude| cmIn an engine, a piston oscillates with simple harmonic motion so that its position varies according to the expression, x = 8.00 cos (5t + TC where x is in centimeters and t is in seconds. (a) At t = 0, find the position of the piston. cm (b) At t = 0, find velocity of the piston. cm/s (c) At t = 0, find acceleration of the piston. cm/s² (d) Find the period and amplitude of the motion. period S amplitude cm
- What is the period of oscillation of a liquid contained in a U tube executing simple harmonic motion?The position of a Simple Harmonic Oscillator based on time is given by x-3.8 cos(5o/4.t+π/6) where t is in seconds and x in meters. Find a) maximum speed and b) maximum acceleration, and c) speed and acceleration at t-0 sec.