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of the circui- Problem #4: Use KCL to calculate the current to passing through the 6k sz resister given below 3/2k_~ Va р) сма 10k wwww Up вкл Y Fo im 3K-

of the circui- Problem #4: Use KCL to calculate the current to passing through the 6k sz resister given below 3/2k_~ Va р) сма 10k wwww Up вкл Y Fo im 3K-

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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I need help with this circuits analysis problem. I used Node Voltage method and got the wrong answer. The correct answer should be 1mA
1 10,000 Va 22,000 Ya 10,000 22,000 Put in Matrix Io = I Vb 10,000 The ам Ғ 10,000 V₁ = 41.5V V₁ = 78.9 V Vb 6x103 + 10,000 answer 19,000 I Va 12,000 V =(- 6х10-3) T +(6x10-3) Va CH U₂ 78.9 (6x10³) = 0 O ((6x103) = 0. 013/5 A is supposed to be IMA. What doing wrong?
Transcribed Image Text:1 10,000 Va 22,000 Ya 10,000 22,000 Put in Matrix Io = I Vb 10,000 The ам Ғ 10,000 V₁ = 41.5V V₁ = 78.9 V Vb 6x103 + 10,000 answer 19,000 I Va 12,000 V =(- 6х10-3) T +(6x10-3) Va CH U₂ 78.9 (6x10³) = 0 O ((6x103) = 0. 013/5 A is supposed to be IMA. What doing wrong?
Problem #4: Use KCL to calculate the curren passing through the 61 resister given below 31/2k Vb- Va lok Use node - volbage since Va-Vb lok Va Om я) 6ма + 10,000 + Va 12K VD вк 1 (Ub-Va) + I 10,000 6,000 I Vp - I Va 10,000 10,000 Von + + 10k + + 6MA = 0 149,000 U₂ we know V₂ = 0 37 6,000 36k Fo V₂ + 1 V₂ 3000 1 1/₂ = 0 V₁ + of the circui- Eq. I Eq. 2 =0 3,000 resistance t to 1 √₂=0 3K-2 Equation I
Transcribed Image Text:Problem #4: Use KCL to calculate the curren passing through the 61 resister given below 31/2k Vb- Va lok Use node - volbage since Va-Vb lok Va Om я) 6ма + 10,000 + Va 12K VD вк 1 (Ub-Va) + I 10,000 6,000 I Vp - I Va 10,000 10,000 Von + + 10k + + 6MA = 0 149,000 U₂ we know V₂ = 0 37 6,000 36k Fo V₂ + 1 V₂ 3000 1 1/₂ = 0 V₁ + of the circui- Eq. I Eq. 2 =0 3,000 resistance t to 1 √₂=0 3K-2 Equation I
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