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of Stanton numb- dtl númber (Pr) is Re) /Pr, b) St = Re ow heat exchange

of Stanton numb- dtl númber (Pr) is Re) /Pr, b) St = Re ow heat exchange

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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d) Decréase the temperature drop of The temperature of a solid surface changes from 27°C to 627°C. The emissive power changes would then increases by the ratio. a) 6:1 b)9:1 c) 27:1 d) 81:1 The definition of Stanton number (St) in terms of Nusselt number (Nu), Reynolds number (Re) and Prandtl númber (Pr) is, a)St = (Nu * Re) /Pr, b) St Re/(Pr*Nu), c) St Nu/(Pr*Re), d) St Nu/(Pr Re) In a counter flow heat exchanger, cold fluid entérs at 30 °C and leaves at 50 °C, whereas the hot fluid enters at 150 °C and leayes at 135 °C. the logarithmic mean temperature v) vi) difference for this case is, a) 20.7°C, b) 80 °C, c) 102.5 °C, d) 55°C
Transcribed Image Text:d) Decréase the temperature drop of The temperature of a solid surface changes from 27°C to 627°C. The emissive power changes would then increases by the ratio. a) 6:1 b)9:1 c) 27:1 d) 81:1 The definition of Stanton number (St) in terms of Nusselt number (Nu), Reynolds number (Re) and Prandtl númber (Pr) is, a)St = (Nu * Re) /Pr, b) St Re/(Pr*Nu), c) St Nu/(Pr*Re), d) St Nu/(Pr Re) In a counter flow heat exchanger, cold fluid entérs at 30 °C and leaves at 50 °C, whereas the hot fluid enters at 150 °C and leayes at 135 °C. the logarithmic mean temperature v) vi) difference for this case is, a) 20.7°C, b) 80 °C, c) 102.5 °C, d) 55°C
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