of Stanton numb- dtl númber (Pr) is Re) /Pr, b) St = Re ow heat exchange
of Stanton numb- dtl númber (Pr) is Re) /Pr, b) St = Re ow heat exchange
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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![d) Decréase the temperature drop of
The temperature of a solid surface changes from 27°C to 627°C. The emissive power
changes would then increases by the ratio.
a)
6:1
b)9:1
c) 27:1 d) 81:1
The definition of Stanton number (St) in terms of Nusselt number (Nu), Reynolds number
(Re) and Prandtl númber (Pr) is,
a)St = (Nu * Re) /Pr, b) St Re/(Pr*Nu), c) St Nu/(Pr*Re), d) St Nu/(Pr Re)
In a counter flow heat exchanger, cold fluid entérs at 30 °C and leaves at 50 °C, whereas
the hot fluid enters at 150 °C and leayes at 135 °C. the logarithmic mean temperature
v)
vi)
difference for this case is,
a)
20.7°C, b) 80 °C, c) 102.5 °C,
d) 55°C](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc45fb84a-03e9-4b61-8ba1-74ca248aec6d%2F5daf3ad1-d910-4cf6-932a-6ef8a9bc85de%2Fi9k4jqq_processed.jpeg&w=3840&q=75)
Transcribed Image Text:d) Decréase the temperature drop of
The temperature of a solid surface changes from 27°C to 627°C. The emissive power
changes would then increases by the ratio.
a)
6:1
b)9:1
c) 27:1 d) 81:1
The definition of Stanton number (St) in terms of Nusselt number (Nu), Reynolds number
(Re) and Prandtl númber (Pr) is,
a)St = (Nu * Re) /Pr, b) St Re/(Pr*Nu), c) St Nu/(Pr*Re), d) St Nu/(Pr Re)
In a counter flow heat exchanger, cold fluid entérs at 30 °C and leaves at 50 °C, whereas
the hot fluid enters at 150 °C and leayes at 135 °C. the logarithmic mean temperature
v)
vi)
difference for this case is,
a)
20.7°C, b) 80 °C, c) 102.5 °C,
d) 55°C
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