of Homogeneity of Variances df1 df2 54 oups ps 3 Sum of Squares 76 Sig. .052 ANOVA df Contrast Coefficients AgeGroup 30 to 39 -1 18 to 29 1 Contrast 1 Mean Square 133.353 20.374 Contrast Tests Value of Contrast F 6.545 400.059 3 1548.437 76 1948.496 79 Contrast Assume equal variances 1 -2.4515 Does not assume equal 1 variances -2.4515 e output provided, can we assume equal variances? Opropriate p-value is < .05 appropriate p-value is > .05 apropriate pavalue is 05 Sig. .001 40 to 49 0 Std. Error t 1.42738 -1.717 1.12255 -2.184 df 34.72

MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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The following output was generated to explore the contrasts specified by the researchers:
Descriptives
Depression
95% Confidence Interval for
Mean
Mean
Std. Deviation Std. Error
Lower Bound Upper Bound
Minimum
Maximum
18 to 29
20
9.7850
2.96074
.66204
8.3993
11.1707
4.86
15.40
30 to 39
20
12.2365
4.05418
.90654
10.3391
14.1339
3.89
21.00
40 to 49
20
14.4460
5.37922
1.20283
11.9284
16.9636
5.92
25.50
50 to 59
20
15.6450
5.23052
1.16958
13.1970
18.0930
5.51
23.65
Total
80
13.0281
4.96634
.55525
11.9229
14.1333
3.89
25.50
Test of Homogeneity of Variances
Contrast Coefficients
Depression
AgeGroup
Levene
30 to 39
Statistic
df1
df2
50 to 59
0
-1
2.764
N
3
Sum of
Squares
76
Sig.
.052
ANOVA
df
18 to 29
1
Contrast
1
Mean Square
133.353
20.374
Contrast Tests
Value of
Contrast
Depression.
Between Groups
400.059
3
1548.437
76
Within Groups
Total
1948.496
79
Contrast
Std. Error
Depression
Assume equal variances
1
-2.4515
1.42738
Does not assume equal 1
variances
-2.4515
1.12255
Based on the output provided, can we assume equal variances?
O No, the appropriate p-value is < .05
Yes, the appropriate p-value is > .05
O No, the appropriate p-value is > .05
O Yes, the appropriate p-value is < .05
F
6.545
Sig.
.001
40 to 49
0
t
-1.717
-2.184
df
76
34.778
Sig. (2-tailed)
.090
.036
Transcribed Image Text:The following output was generated to explore the contrasts specified by the researchers: Descriptives Depression 95% Confidence Interval for Mean Mean Std. Deviation Std. Error Lower Bound Upper Bound Minimum Maximum 18 to 29 20 9.7850 2.96074 .66204 8.3993 11.1707 4.86 15.40 30 to 39 20 12.2365 4.05418 .90654 10.3391 14.1339 3.89 21.00 40 to 49 20 14.4460 5.37922 1.20283 11.9284 16.9636 5.92 25.50 50 to 59 20 15.6450 5.23052 1.16958 13.1970 18.0930 5.51 23.65 Total 80 13.0281 4.96634 .55525 11.9229 14.1333 3.89 25.50 Test of Homogeneity of Variances Contrast Coefficients Depression AgeGroup Levene 30 to 39 Statistic df1 df2 50 to 59 0 -1 2.764 N 3 Sum of Squares 76 Sig. .052 ANOVA df 18 to 29 1 Contrast 1 Mean Square 133.353 20.374 Contrast Tests Value of Contrast Depression. Between Groups 400.059 3 1548.437 76 Within Groups Total 1948.496 79 Contrast Std. Error Depression Assume equal variances 1 -2.4515 1.42738 Does not assume equal 1 variances -2.4515 1.12255 Based on the output provided, can we assume equal variances? O No, the appropriate p-value is < .05 Yes, the appropriate p-value is > .05 O No, the appropriate p-value is > .05 O Yes, the appropriate p-value is < .05 F 6.545 Sig. .001 40 to 49 0 t -1.717 -2.184 df 76 34.778 Sig. (2-tailed) .090 .036
Reconsider the output provided from the previous question:
Descriptives
Depression
Mean
Std. Deviation
18 to 29
20
9.7850
2.96074
30 to 39
20
12.2365
4.05418
40 to 49
20
14.4460
5.37922
20
15.6450
5.23052
50 to 59
Total
80 13.0281
4.96634
Test of Homogeneity of Variances
Depression
Levene
Statistic
df1
df2
2.764
N
3
Sum of
Squares
76
Sig.
.052
ANOVA
df
95% Confidence Interval for
Mean
Lower Bound
Upper Bound
8.3993
11.1707
10.3391
14.1339
11.9284
16.9636
13.1970
18.0930
11.9229
14.1333
Contrast Coefficients
Age Group
30 to 39
-1
3
Std. Error
.66204
.90654
1.20283
1.16958
55525
Contrast
1
Mean Square
133.353
20.374
Contrast Tests
Value of
Contrast
18 to 29
F
6.545
Depression
Between Groups
400.059
Within Groups
1548.437
76
Total
1948.496
79
Contrast
Std. Error
Depression Assume equal variances
1
-2.4515
1.42738
Does not assume equal 1
variances
-2.4515
1.12255
Complete the following sentence by using the drop-down options.
The planned contrasts is [Select ]
[Select]
[Select]
[Select]
, p =
Sig.
.001
Minimum
4.86
3.89
5.92
5.51
3.89
50 to 59
0
40 to 49
0
t
-1.717
76
-2.184 34.778
df
Maximum
15.40
21.00
25.50
23.65
25.50
Sig. (2-tailed)
090
.036
Transcribed Image Text:Reconsider the output provided from the previous question: Descriptives Depression Mean Std. Deviation 18 to 29 20 9.7850 2.96074 30 to 39 20 12.2365 4.05418 40 to 49 20 14.4460 5.37922 20 15.6450 5.23052 50 to 59 Total 80 13.0281 4.96634 Test of Homogeneity of Variances Depression Levene Statistic df1 df2 2.764 N 3 Sum of Squares 76 Sig. .052 ANOVA df 95% Confidence Interval for Mean Lower Bound Upper Bound 8.3993 11.1707 10.3391 14.1339 11.9284 16.9636 13.1970 18.0930 11.9229 14.1333 Contrast Coefficients Age Group 30 to 39 -1 3 Std. Error .66204 .90654 1.20283 1.16958 55525 Contrast 1 Mean Square 133.353 20.374 Contrast Tests Value of Contrast 18 to 29 F 6.545 Depression Between Groups 400.059 Within Groups 1548.437 76 Total 1948.496 79 Contrast Std. Error Depression Assume equal variances 1 -2.4515 1.42738 Does not assume equal 1 variances -2.4515 1.12255 Complete the following sentence by using the drop-down options. The planned contrasts is [Select ] [Select] [Select] [Select] , p = Sig. .001 Minimum 4.86 3.89 5.92 5.51 3.89 50 to 59 0 40 to 49 0 t -1.717 76 -2.184 34.778 df Maximum 15.40 21.00 25.50 23.65 25.50 Sig. (2-tailed) 090 .036
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