Litter sizes (number of pups) for randomly chosen dogs from two breeds were compared. The sample data were entered into Excel, and the following resultswere producedt-Test: Two-Sample Assuming Unequal VariancesDalmatianMeanVarianceObservationsHypothesized Mean Diffdft statMultiple Choiceless than 10.more than 10.4.81253.4958333between 10 and 05.16021What is the p-value for a left-tailed test comparing the means at a = .05?-1.261183Labrador5.4615380.60256413

The question is about hypothesis testing.Given :Test statistic ( t ) = -1.261183df = 21

Answered: Litter sizes (number of pups) for…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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An experiment has been conducted for four treatments with eight blocks. Complete the following analysis of variance table (to 2 decimals but p-value to 4 decimals, if necessary). If answer is zero enter "0". Source Sum Degrees Mean of Variation of Squares of Freedom Square F p-value Treatments 1,000 Blocks 600 Error Total 1900 Use a = 0.05 to test for any significant differences. The p-value is - Select your answer - What is your conclusion? Select your answer - 0- Icon Key
Two accounting professors decided to test if the variance of their grades is different or no. To accomplish this, they each graded the same 10 exams with the following results: Standard Deviation 22.4 Mean Grade Professor 1 79.3 Professor 2 82.1 12.0 F What is the P-value of the test? Select one: a. between 0.01 and 0.025 Ob. between 0.025 and 0.05 C. between 0.05 and 0.10 Od. bigger than 0.10
Given below are the analysis of variance results from a Minitab display. Assume that you want to use a 0.05 significance level in testing the null hypothesis that the different samples come from populations with the same mean. Identify the p-value. Source DF SS MS F Factor 3 30 10.00 1.6 0.264 Error 50 6.25 Total 11 80 O A. 6.25 O B. 1.6 OC. 10.00 O D. 0.264 Click to select your answer. étv MacBook Air F10 F9 F7 30 888 *- F6 F3 esc F1 F2 & @ 7 4 5 2 3.
Heights The heights (cm) in the following table are from Data Set 1 “Body Data” in Appendix B. Results from two-way analysis of variance are also shown. Use the displayed results and use a 0.05 significance level. What do you conclude? XLSTAT
Use the Excel printout to answer the following questions. t-Test: Two-Sample Assuming Equal Variances E Variable 1 Variable 2 Mean 28.671 28.215 Variance 5.061 2.225 Observations 8 7 Pooled Variance 3.752 Hypothesized Mean Difference df 13 t Stat 0.455 P(T <= t) one-tail 0.328 t Critical one-tail 1.771 P(T <= t) two-tail 0.657 t Critical two-tail 2.160 In testing for a difference between the two population means, would you conclude that the assumption of a common variance is reasonable? O Yes, the ratio of the the larger variance to the smaller variance is less than three. O Yes, the ratio of the larger variance to the smaller variance is more than three. O No, the ratio of the larger variance to the smaller variance is less than three. O No, the ratio of the larger variance to the smaller variance is more than three. O It is not possible to check that assumption with the given information. What is the observed value of the test statistic? t = What are the degrees of freedom for the…
Class 1 Final Sample Size: 30 Sample Variance: 80.55 Sample Mean: 44.2917 Class 2 Final Sample Size:30 Sample Variance: 55.29 Sample Mean: 36.4833 The assignment says to use the Z test for means and assume the hypothesized difference is 0. 1. Is there a significant difference in the means of the two finals at the .01 level of significance? 2. Why or why not?
Q9 For the following data: 16 32 8 28 12 20 18 Find the following: (a) Sample Variance (b) Sample Standard Deviation (c) Coefficient of Variation
In a hypothesis test for the population variance, the alternate hypothesis is the population variance doesn't equal 17.0. The significance level to be used is 0.05 and the sample size to be taken is 25. The table value(s) to use from the chi-square distribution is/are 12.401 and 39.364. 13.181 39.364 40.671
A real estate agent believes that the mean home price in the northern part of a county is higher than the mean price in the southern part of the county and would like to test the claim. A simple random sample of housing prices is taken from each region. The results are shown below. Mean Variance Observations Southern Northern 155.056 168.889 345.938 560.928 18 Pooled Variance 453.433 Hypothesized Mean Difference df 34 1949 t Stat P(T<=t) one-tail p= Ex: 1.234 0.030 2.441 0.060 t Critical one-tail P(T<=t) two-tail t Critical two-tail 2.728 2. Confidence Level 99% t = Ex: 1.234 n= Ex: 9 Degrees of freedom: df = Point estimate for the southern part of the county: 1 Ex: 1.234 Point estimate for the northern part of the county: 2 0耳_ 国 23 72°F
If there is significantly more variability between samples than within samples , this tends to be indicative of : 1 use of an inefficient study design. 2. actual mean differences attributed to the factor. 3. incidental differences attributed to samplig error. 4. actual variance difference attribute to different samples.
please assist I am lost
A researcher wants to measure average cardiovascular health of university students and compare those scores to the average scores in the general population. Assuming that population variance is known, what statistical test is most appropriate for this study? independent-samples t-test single-sample t-test z-test for sample mean related-samples t-test

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