of a request is 1.8 seconds. Using M/M/1 queue to model the access delay in the 5.5Mb link. The formula for the average response time is E[T]=1(p- A), where A is the arrival ra cts to the access link and p is the service rate of the access link. origin servers
of a request is 1.8 seconds. Using M/M/1 queue to model the access delay in the 5.5Mb link. The formula for the average response time is E[T]=1(p- A), where A is the arrival ra cts to the access link and p is the service rate of the access link. origin servers
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
Related questions
Question
see image
![Question#6:
Consider the networks shown in the figure below. Assume computers in the institution send out
28 requests per second. Each object average size is 100,000 bits. Also assume the internet side
delay of a request is 1.8 seconds. Using M/M/1 queue to model the access delay in the 5.5Mbps
access link. The formula for the average response time is E[T]=1u- A), where A is the arrival rate
of objects to the access link and u is the service rate of the access link.
origin
|servers
public
Internet
5.5 Mbps
access link
institutional
network
100Mbps LAN
D D institutional
cache
1. Find the total average response time when no institutional cache is used. [Note: you
should also use the M/M/1 queue formula to calculate the delay in internal Ethernet LAN.]
2. Now suppose the institutional cache is used. The hit rate for the cache is 0.8. Find the
total average response time.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff8a79bc5-e0ae-4718-92d6-fc74e9d7e600%2F44624f06-e979-4da6-8c54-ca8b75b52002%2Fcdsa9y_processed.png&w=3840&q=75)
Transcribed Image Text:Question#6:
Consider the networks shown in the figure below. Assume computers in the institution send out
28 requests per second. Each object average size is 100,000 bits. Also assume the internet side
delay of a request is 1.8 seconds. Using M/M/1 queue to model the access delay in the 5.5Mbps
access link. The formula for the average response time is E[T]=1u- A), where A is the arrival rate
of objects to the access link and u is the service rate of the access link.
origin
|servers
public
Internet
5.5 Mbps
access link
institutional
network
100Mbps LAN
D D institutional
cache
1. Find the total average response time when no institutional cache is used. [Note: you
should also use the M/M/1 queue formula to calculate the delay in internal Ethernet LAN.]
2. Now suppose the institutional cache is used. The hit rate for the cache is 0.8. Find the
total average response time.
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