offod mass10 kgTength L = 6 Manguiaŏ velocity w= 8 Bad'scalculate comPonent of deactionmagnitude of vedticalon the 8od at Point oSign convention

Answered: Image /qna-images/answer/b97a3fb4-4950-433a-9715-c4e28c966fff.jpg

Answered: of 8od mass 10 kg Tength i = 6 M anguad…

of 8od mass 10 kg Tength i = 6 M anguad velocity = 3 Bads calculate magnitude of vestical component of on the 8od at Point o Sign convention

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Related questions

Q: Write the equation which will represent conservation of angular momentum.

A: Conservation of angular momentum: The law of angular momentum conservation states that there will be…

Q: Plot the following coordinates, identify the point and draw a box 1. P(5, -7, 4 ) 2. P(-4, -5, -6 )

A: Co-ordinates are mentioned on x y z plane. Subsequently, boxes are drawn.

Q: nasses m1, m2.m3 and m4 0 kg, 240 kg and 260 kg aly. The corresponding radi e 0.2 m, 0.15 m, 0.25 m…

A: Given : m1= 200 kg m2= 300 kg m3= 240 kg m4= 260 kg r1=0.2 m r2= 0.15 m r3 = 0.25 m r4 = 0.3 m…

Q: The 5 lb box is projected with a speed of 20 ft/s at point "A" up the smooth vertical circular…

Q: Due to an increase in power, the motor M rotates the shaft A shown in (Figure 1) with an angular…

Q: s1f the SYStem is Isulated the angluas Momentum will be Constant in Magnitude pat direction 1-true…

Q: 5. Find the new location of point G; initially at G = [3 0 -1] If, (i) it is rotated by 60deg. about…

Q: Calculate the tangential component at of the acceleration.

A: radius r = 95 mspeed V = 105 km/h= 29.16 m/stime t1=17 st2 = 10s

Q: For this question assume that there is only one main landing gear touching to ground at one point.…

A: The jet is in the beginning condition, which indicates there will be no thrust acting on the jet due…

Q: Equation of the hill. Y = 20(1 - x²/6400) with the car travelling at 9m/s. The x distance travelled…

Q: Find the velocity of car Mass=2 kg K.E=40 J

A: Given data : Mass=m Kinetic energy=K.E Required : Velocity of car

Q: Q3 product the mass with velocity * named linear momentum OC momentum O acceleration

A: mass =m (kg) velocity=v (m/s) acceleration is change in velocity/time so acceleration is wrong

Q: Y A projectile is fired with an initial velocity of No (m/sec) upward at an angle (0) with the…

A: To find: The horizontal distance covered before the projectile returns to its original level and the…

Q: A frain start from rest at Stadion A & accelerate C@ 0.75 m/s for 40s.Ater thet if freue ls, with…

Q: A body rotates according to the relation a=2t; where a is in rad/sec^2 and t is in sec. W =4 rad/sec…

A: Given Data The angular acceleration of the body is: The angular acceleration can be written as…

Q: The in-plane angular speed of the bent bar indicated below is w = 0.2 rad/s. The dimensions of the…

Q: Ap B. Az B2 Bx Cz By Ax Dy Dx The line of action of force F passes through points A and B. Find the…

Q: Ay= A 8 y Eat Ice Cream X N An advertisement can be modelled as a thin plate with uniform density…

A: The density of plate is The dimension of plate is

Concept explainers

Free Body Diagram

The system of forces acting on a body tends to either rotate it or make the body undergo motion. In general, when an external agent exerts a force on a body, the body undergoes translational motion and rotational motion. The body has six degrees of freedom under the influence of that force. Here, three degrees of freedom are from the translational motion while the other three are from the rotation motion. However, sometimes the bodies are not allowed to undergo any motion and are fixed, under such conditions the body is said to be constrained.

Question

of
fod mass
10 kg
Tength L = 6 M
anguiaŏ velocity w= 8 Bad's
calculate comPonent of deaction
magnitude of vedtical
on the 8od at Point o
Sign convention

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step by step

Solved in 2 steps with 1 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.

Similar questions

Qu The rotor of atraction motor of an electric train has amass of 450 kg and is Supported 75o nmu apart. The radius . f gyrutian f thu rotur is on two bearings 180 mu and its axis is parallel t. the axle of the track wkeels. The wotor rotates at 1500 r.pm. when the train negotiates acurve of 200m radiur at /o km/hr Deteramine the magnetudeand direction of change in hearing Vactions while neg.tiating the Curve.
This is a dynamics question. Made a mistake submitting it last time. Hints: wA=wf+wA/fwA=wf+wA/f, ans. vC=-7.5 i m/s, aC=85 i - 7.5j m/s2
For the diagram below the angular velocity of the wheel is w = 2rad/s. The location of the instantaneous center of zero velocity is at point 0.3 m OD 1.2 m OB 45% O somewhere not listed in the other options. OC 0.3 m C
QsI The whel of mutuv Cy cle and the engine parts have antoncent •f inertia 2-5 kgm? and o I5 ky.m respectively The axis of rotation of the engine erant Shaft is parallel to thatof the road wheels-IR the gear ratio is 5:1 and the diameter o f the road whels is o5m, find the magnitude anal divection . f the gyroscopic Couple when the motor Cycle rounds a Curve of 3om radius at 16 mls.
P5/ The wheel of metor Cycle and the engine parts have antoment of inertia 2-5 kg.m? and o 15 Kg.m² respectively The axis of rotation of the engine erank Shaft is parallel to that of the road wheels-If the gear ratio is 5:1 and the diameter o f the read whels is o.65 m, find the magnitude and direction of the gyroscopic Couple when the motor Cycle rounds a eurve of Bom radius at l6 m/s.
Qul The rotor ef atraction pmotor of an electric train has amass of 450 kg and is Supported on two bearings The radius of gyrution f thu rotor is 75o nm apart. 180 mw and its axis is parallel t. the axle of the track wkeels. The wotor rotates at 1500r.pm. hen the train negotiates acurveof 200m Vadiur at lok/hr Deteramine the magnetudeand divection of change in henring Veactions while neg.tiating the Curve.
dr Grubler's planar mcchanism to be one. mentioned arrangement is 3- 3:9 18- Ya) 0 (b) 1 (c) 2 (d) 3 メケ J.
rerce D6 =blank Dimetr Yedaction Fn =0015 Y(Pi-CDp Ev-vam velocity PP- Panch Diametr FELt Ye Sreching force woling force drawing foreo 2. 25 ower Kx=0.98+o.02 Rd=die corner vadus mui die shape facArin extrustion -Lentn tthicknes YA=Stess ) Dirct on 1 The data given in Table Q1(a) corresponds to a cold heading operation performed to make square head on a steel bolt. Figure Q1(a) shows the dimensions of the bolt to be produced. Strength coefficient for the steel Table Q1(a) Strain hardening exponent 550 MPa Coefficient of friction at the die-work interface- 0.21 Thickness of wire stock out of which the bolt is made 0.16 Final length of the bolt. 10 mm 120 mm Compute: (i) The length of stock must project out of the die in order to provide sufficient volume of material for this upsetting operation. (ii) The total number of bolts that can be made out of 6 m rod (wire stock) (iii) The maximum force that the punch must apply to form the head 5 mm 10 mm 15 mm Figure Q1(a)
A hoop of radius 95mm and mass 100g is rotated via a capacitor driven power source with P(t)=1.61e-1.3tW. (since it is a hoop, it is a special case, and r=rG) Assuming the hoop is accelerated from rest, determine the rotational velocity after t=8.5s. [rad.s-1] Determine the rotational speed of the hoop after t=8.5s if the power source acts to roll the particle from rest on a horizontal surface. [rad.s-1]
i need the answer quickly
Q. For the Shown mechani l system, Find Hthe reledion between F and X Youd Xx Then draw the block diagram. M, K, MA K2
Component and centrfugal force: A - 15 000 xg B - 1000 xg C - 400 xg D - 2500 xg Two centrifuge are available. Centrifuge 1 has r= 7cm anda maximum speed of 3500 rpm centrifuge 2 has a r= 9cm and a max speed of 14500 rpm. Construct a separation scheme of the four components:1. using only two centrifugation steps 2. four components are separated into supernatant 1, supernatant 2, pellet 1, and pellet 2. 3. the two centrifuge machine must be used in the procedure