Of 100 students, 26 can speak French F, 33 can speak German G, and 16 can speak both French and German. If a student is picked at random, what is the probability that he or she can speak French or German? Pr(FUG): Pr(FUG) = 59 100 43 Pr(FUG) = 100 49 Pr(FUG): 100 = 21 Pr(FG) - 50
Of 100 students, 26 can speak French F, 33 can speak German G, and 16 can speak both French and German. If a student is picked at random, what is the probability that he or she can speak French or German? Pr(FUG): Pr(FUG) = 59 100 43 Pr(FUG) = 100 49 Pr(FUG): 100 = 21 Pr(FG) - 50
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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![Of 100 students, 26 can speak French F, 33 can speak German G, and 16 can speak both French and German.
If a student is picked at random, what is the probability that he or she can speak French or German?
Pr(FUG):
Pr(FUG)
=
59
100
43
Pr(FUG) = 100
49
- 100
Pr(FUG):
21
Pr(FUG)= 50
=](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fadec6c6e-501b-48cc-a2bc-9a336b200c25%2F50227641-7d26-4b19-b087-fe8df25061c0%2Fl8lw8za_processed.png&w=3840&q=75)
Transcribed Image Text:Of 100 students, 26 can speak French F, 33 can speak German G, and 16 can speak both French and German.
If a student is picked at random, what is the probability that he or she can speak French or German?
Pr(FUG):
Pr(FUG)
=
59
100
43
Pr(FUG) = 100
49
- 100
Pr(FUG):
21
Pr(FUG)= 50
=
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