If 3 people are randomly selected from all the people in the four cities, what is the probability that the first two people are from Edmonds AND the last person is from Shoreline?

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Welcome to our Educational Resource Page! Here we will go through a problem set involving population data from four cities in Washington State. Follow along to better understand probability in a real-world context.

The current populations of the cities of Edmonds, Kenmore, Lynnwood, and Shoreline in Washington state are shown below in thousands of people.

### Population Data

#### Population Graph (in thousands)

The graph below presents the population figures for four cities. The y-axis represents the population in thousands, and the x-axis lists the cities: Edmonds, Kenmore, Lynnwood, and Shoreline. 

1. **Edmonds** - 42.767 thousand people
2. **Kenmore** - 23.093 thousand people
3. **Lynnwood** - 38.511 thousand people
4. **Shoreline** - 56.752 thousand people

![Graph of Population](image-url)

### Questions and Solutions

**a. If 1 person is randomly selected from all the people in these four cities, what is the probability that the person is from Shoreline?**

To find this probability, we need to know the total population and the population of Shoreline.

**Total Population:**
- Edmonds: 42.767 thousand
- Kenmore: 23.093 thousand
- Lynnwood: 38.511 thousand
- Shoreline: 56.752 thousand

Sum = 42.767 + 23.093 + 38.511 + 56.752 = 161.123 thousand

**Probability:**
\[ \text{P(Shoreline)} = \frac{\text{Population of Shoreline}}{\text{Total Population}} = \frac{56.752}{161.123} = 0.3523 \]

Thus, the probability is approximately **0.3523** or **35.23%**.

**b. If 1 person is randomly selected from all the people in these four cities, what is the probability that the person is from Shoreline OR from Kenmore?**

**Probability:**
\[ \text{P(Shoreline or Kenmore)} = \frac{\text{Population of Shoreline} + \text{Population of Kenmore}}{\text{Total Population}} = \frac{56.752 + 23.093}{161.123} = \frac{79.845}{161.123} = 0.495
Transcribed Image Text:Welcome to our Educational Resource Page! Here we will go through a problem set involving population data from four cities in Washington State. Follow along to better understand probability in a real-world context. The current populations of the cities of Edmonds, Kenmore, Lynnwood, and Shoreline in Washington state are shown below in thousands of people. ### Population Data #### Population Graph (in thousands) The graph below presents the population figures for four cities. The y-axis represents the population in thousands, and the x-axis lists the cities: Edmonds, Kenmore, Lynnwood, and Shoreline. 1. **Edmonds** - 42.767 thousand people 2. **Kenmore** - 23.093 thousand people 3. **Lynnwood** - 38.511 thousand people 4. **Shoreline** - 56.752 thousand people ![Graph of Population](image-url) ### Questions and Solutions **a. If 1 person is randomly selected from all the people in these four cities, what is the probability that the person is from Shoreline?** To find this probability, we need to know the total population and the population of Shoreline. **Total Population:** - Edmonds: 42.767 thousand - Kenmore: 23.093 thousand - Lynnwood: 38.511 thousand - Shoreline: 56.752 thousand Sum = 42.767 + 23.093 + 38.511 + 56.752 = 161.123 thousand **Probability:** \[ \text{P(Shoreline)} = \frac{\text{Population of Shoreline}}{\text{Total Population}} = \frac{56.752}{161.123} = 0.3523 \] Thus, the probability is approximately **0.3523** or **35.23%**. **b. If 1 person is randomly selected from all the people in these four cities, what is the probability that the person is from Shoreline OR from Kenmore?** **Probability:** \[ \text{P(Shoreline or Kenmore)} = \frac{\text{Population of Shoreline} + \text{Population of Kenmore}}{\text{Total Population}} = \frac{56.752 + 23.093}{161.123} = \frac{79.845}{161.123} = 0.495
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