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of 1.00 x10-4 M Ag* and 5.00 x10-5 M Cro42, Ag2CrO4 precipita= of 1.0 x10-4 M Ag* and 1.0 x10-4 M I03", Ag(103) precipitate willf y of Ag2CrO4 is lower than the solubility of Ag(1O3). of 0.200 M CrO42- and 0.200 M 103', Ag2(CrO4) will precipitate ove mixture.

of 1.00 x10-4 M Ag* and 5.00 x10-5 M Cro42, Ag2CrO4 precipita= of 1.0 x10-4 M Ag* and 1.0 x10-4 M I03", Ag(103) precipitate willf y of Ag2CrO4 is lower than the solubility of Ag(1O3). of 0.200 M CrO42- and 0.200 M 103', Ag2(CrO4) will precipitate ove mixture.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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The Ksp values of silver chromate Ag2Cro4 and silver iodate Ag(IO3) are given below. Ag2Cro4 Ag(IO3) 1.12 x 1012 3.17 x 10°8 Ksp Based on these Ksp values, which of the following is true? In the solution consisting of 1.00 x10-4 M Ag* and 5.00 x10-5 M Cro42", Ag2Cro4 precipitate will form. In the solution consisting of 1.0 x10-4 MAg* and 1.0 x10-4 M I03", Ag(IO3) precipitate will form. In pure water, the solubility of Ag2CrO4 is lower than the solubility of Ag(IO3). In the solution consisting of 0.200 M CrO42- and 0.200 M 103', Ag2(CrO4) will precipitate first if we add Ag* ions gradually into the above mixture.
Transcribed Image Text:The Ksp values of silver chromate Ag2Cro4 and silver iodate Ag(IO3) are given below. Ag2Cro4 Ag(IO3) 1.12 x 1012 3.17 x 10°8 Ksp Based on these Ksp values, which of the following is true? In the solution consisting of 1.00 x10-4 M Ag* and 5.00 x10-5 M Cro42", Ag2Cro4 precipitate will form. In the solution consisting of 1.0 x10-4 MAg* and 1.0 x10-4 M I03", Ag(IO3) precipitate will form. In pure water, the solubility of Ag2CrO4 is lower than the solubility of Ag(IO3). In the solution consisting of 0.200 M CrO42- and 0.200 M 103', Ag2(CrO4) will precipitate first if we add Ag* ions gradually into the above mixture.
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