Octane (CH,3) is a straight chain of carbon atoms with no dipole moment and a boiling point of 125°C. Water has a dipole moment, has hydrogen bonds and has a boiling point of 100°C. The difference between these two boiling points can best be rationalized by: A. Intermolecular forces between molecules with dipole moments are greater than between molecules with no dipole moment B. Hydrogen bonding is a strong intermolecular force C. London dispersion forces are weak but there are many LDFS in octane so the net IMF in CH18 is greater than the net IMF in H,0 D. London dispersion forces are strong and so the boiling point of octane is greater than the boiling point of water E. There is no trend, this is a magical mystery of science
Octane (CH,3) is a straight chain of carbon atoms with no dipole moment and a boiling point of 125°C. Water has a dipole moment, has hydrogen bonds and has a boiling point of 100°C. The difference between these two boiling points can best be rationalized by: A. Intermolecular forces between molecules with dipole moments are greater than between molecules with no dipole moment B. Hydrogen bonding is a strong intermolecular force C. London dispersion forces are weak but there are many LDFS in octane so the net IMF in CH18 is greater than the net IMF in H,0 D. London dispersion forces are strong and so the boiling point of octane is greater than the boiling point of water E. There is no trend, this is a magical mystery of science
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter10: Liquids And Solids
Section: Chapter Questions
Problem 1RQ: What are intermolecular forces? How do they differ from intramolecular forces? What are...
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![Octane (C,H18) is a straight chain of carbon atoms with no dipole
moment and a boiling point of 125°C. Water has a dipole moment,
has hydrogen bonds and has a boiling point of 100°C. The difference
between these two boiling points can best be rationalized by:
18
A. Intermolecular forces between molecules with dipole moments
are greater than between molecules with no dipole moment
B. Hydrogen bonding is a strong intermolecular force
C. London dispersion forces are weak but there are many LDFS in
octane so the net IMF in C,H1, is greater than the net IMF in H,0
D. London dispersion forces are strong and so the boiling point of
octane is greater than the boiling point of water
E. There is no trend, this is a magical mystery of science](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1b490487-c171-4fa1-a162-f0ff1460ac56%2F6620bf37-1e66-4805-b6ef-977ab20ad3f3%2Ftuy3mxr_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Octane (C,H18) is a straight chain of carbon atoms with no dipole
moment and a boiling point of 125°C. Water has a dipole moment,
has hydrogen bonds and has a boiling point of 100°C. The difference
between these two boiling points can best be rationalized by:
18
A. Intermolecular forces between molecules with dipole moments
are greater than between molecules with no dipole moment
B. Hydrogen bonding is a strong intermolecular force
C. London dispersion forces are weak but there are many LDFS in
octane so the net IMF in C,H1, is greater than the net IMF in H,0
D. London dispersion forces are strong and so the boiling point of
octane is greater than the boiling point of water
E. There is no trend, this is a magical mystery of science
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