CaseIT firm HelpTech offers technical support for corporate clients across the country. The number ofbilled hours (in th) in the past 4 years are presented below.246 255 256 245 239Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec2020 205 206 206 205 205 212 2202019 194 197 191 1932018 196 192 192 2032017 186 187 166 175193 202 209 214 210 206 199 199204 212 217 216 217 202 197 199187 213 225 209 209 216 206 198Obtain the seasonal indexes for Jan '20 to Dec '20 using all 4 years. Select the indexyou obtained for Apr '20: Obtain the optimal parameters (alpha and beta) using Excel's Solver that wouldminimize the previously calculated 2020 MSE.alpha = 1, beta = 0alpha=0.342, beta = 0.631alpha=0, beta 1alpha 0.908, beta = 0.337=

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Answered: Obtain the optimal parameters (alpha…

MATLAB: An Introduction with Applications

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Chapter1: Starting With Matlab

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(3) The approximate enrollment, in millions between the years 2009 and 2018 is provided by a linear model Y3D0.2309x+18.35 Where x-0 corresponds to 2009, x=1 to 2010, and so on, and y is in millions of students. Use the model determine projected enrollment for the year 2014. 近

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In a certain region, about 6% of a city's population moves to the surrounding suburbs each year, and about 2% of the suburban population moves into the city. In 2020, there were 9,750,000 residents in the city and 900,000 residents in the suburbs. Set up a difference equation that describes this situation, where x is the initial population in 2020. Then estimate the populations in the city and in the suburbs two years later, in 2022. (Ignore other factors that might influence the population sizes.) Set up a difference equation that describes this situation, where x is the initial population in 2020. x₁ = Mx0 = (Type an integer or decimal for each matrix element. Do not perform the calculation.)
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Obtain the optimal parameters (alpha and beta) using Excel's Solver that would minimize the previously calculated 2020 MSE. alpha = 1, beta = 0 alpha= 0.342, beta = 0.631 alpha=0, beta 1 alpha 0.908, beta = 0.337 =