Obtain the equilibrium constant for the reactionHCN(ag) - H* (ag) + CN (ag)From the following:HCN(g) + он (аg) CN (ag) + H,0(), к, — 4.9 х 104На О() — н (аg) + Он (ад), К, %3D1.0 х 10Equilibrium constant =

When two chemical equations are added to get the net chemical equation, then the equilibrium constant of net chemical equation is obtained by multiplying individual Kc values.

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Obtain the equilibrium constant for the reaction HCN(ag) - H* (ag) + CN (ag) From the following: HCN(aq) + OH (ag) – CN (ag) + H2O(1), K1 = 4.9 × 104 H2O(1) → H* (aq) + OH (ag), K2 = 1.0 × 10 4 Equilibrium constant

Obtain the equilibrium constant for the reaction HCN(ag) - H* (ag) + CN (ag) From the following: HCN(aq) + OH (ag) – CN (ag) + H2O(1), K1 = 4.9 × 104 H2O(1) → H* (aq) + OH (ag), K2 = 1.0 × 10 4 Equilibrium constant

Chemistry

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ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

Obtain the equilibrium constant for the reaction
HCN(ag) - H* (ag) + CN (ag)
From the following:
HCN(g) + он (аg) CN (ag) + H,0(), к, — 4.9 х 104
На О() — н (аg) + Он (ад), К, %3D1.0 х 10
Equilibrium constant =

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