Observe the graph below. According to the chart shown above, if the saturated solution of glucose at 80°C was suddenly cooled to 40°C, what would happen? Solubility of Glucose in Water 600 500 400 300 200 100 20 40 60 80 100 Temperature (Celsius) An additional 300 grams of glucose could dissolve. The solution would spontaneously cool to 200°C. The solution becomes supersaturated. Nothing special would happen; the increased temperature just made the dissolving process quicker. Dissolved Mass (grams)

Observe the graph below. According to the chart shown above, if the saturated solution of glucose at 80°C was suddenly cooled to 40°C, what would happen? Solubility of Glucose in Water 600 500 400 300 200 100 20 40 60 80 100 Temperature (Celsius) An additional 300 grams of glucose could dissolve. The solution would spontaneously cool to 200°C. The solution becomes supersaturated. Nothing special would happen; the increased temperature just made the dissolving process quicker. Dissolved Mass (grams)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Which of the following is a proper procedure for creating a supersaturated solution of potassium nitrate if you have 100g of water and 80g of potassium nitrate available? Add all of the solute to 100g of water and stir for an extremely long time. Add all of the solute to 100g of water and heat it up past 48 degrees C. Add all of the solute to 100g of water & heat it up past 48 degrees C. Make sure everything dissolves, and then carefully cool it down below 48 degrees C. Add all of the solute to 100g of water & heat it up just over 35 degrees C. Once everything dissolves, cool it down to below 35 degrees C. It is impossible to make a supersaturated solution of potassium nitrate with 80g of solute & 100g of water.
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The boiling point of water is 100.0°C at 1 atmosphere. How many grams of potassium iodide (166.0 g/mol), must be dissolved in 242.0 grams of water to raise the boiling point by 0.500 °C? Refer to the table for the necessary boiling or freezing point constant. Kb(°C/m) Kƒ(°C/m) Solvent Formula Mass = H₂O CH3 CH₂OH Water 0.512 Ethanol 1.22 Chloroform CHCl3 3.67 Benzene C6H6 2.53 Diethyl ether CH3 CH₂ OCH2 CH3 2.02 g potassium iodide 1.86 1.99 5.12
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