An osmosis experiment uses aqueous solutions of 0.60 M glucose (non-electrolyte) and 0.40 M Naci (strong electrolyte). These two solutions are placed in a U-shape tube separated by a semipermeable membrane. Initially, these two solutions have the same height (Initial state) as shown in the picture below. After the osmosis process reaches equilibrium (Final state in the picture), the solution on left becomes higher than the solution on right. tatate le Final state Soton Setona Selution Semipemtemenrane len Which of the following statements is correct regarding this osmosis experiment? Initially Solution A is 0.60 M glucose and Solution B 0.40 M NaCI. During the osmosis, more water molecules flow " across the semipermeable membrane to the left side of the U-shape tube. Initially Solution A is 0.60 M glucose and Solution B 0.40 M NaCI. During the osmosis, NaCI molecules flow across *the semipermeable membrane to the left side of the U-shape tube. Initially Solution A is 0.40 M NaCl and Solution B is 0.60 M glucose . During the osmosis, glucose molecules flow * across the semipermeable membrane to the left side of the U-shape tube. Initially Solution A is 0.40 M NaCl and Solution B is 0.60 M glucose. During the osmosis, more water `molecules flow across the semipermeable membrane to the left side of the U-shape tube. Initially Solution A is 0.40 M NaCl and Solution B is 0.60 M glucose. During the osmosis, NaCl molecules flow to the right side and glucose molecules flow to the left hand side.

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An osmosis experiment uses aqueous solutions of 0.60 M glucose (non-electrolyte) and 0.40 M NaCl (strong electrolyte). These two solutions are placed in a U-shape tube separated by a semipermeable membrane. Initially, these two solutions have the same height (initial state) as shown in the picture below. After the osmosis process reaches equilibrium (final state in the picture), the solution on the left becomes higher than the solution on the right.

**Diagrams Explanation:**

1. **Initial State Diagram:**
   - The U-shaped tube contains Solution A on the left and Solution B on the right.
   - Both solutions are at the same height.
   - A semipermeable membrane separates the two solutions.

2. **Final State Diagram:**
   - The left side (Solution A) shows a higher liquid level compared to the right side (Solution B).
   - The semipermeable membrane remains between the two solutions.

**Question:**

Which of the following statements is correct regarding this osmosis experiment?

- **A.** Initially Solution A is 0.60 M glucose and Solution B 0.40 M NaCl. During the osmosis, more water molecules flow across the semipermeable membrane to the left side of the U-shape tube.

- **B.** Initially Solution A is 0.60 M glucose and Solution B 0.40 M NaCl. During the osmosis, NaCl molecules flow across the semipermeable membrane to the left side of the U-shape tube.

- **C.** Initially Solution A is 0.40 M NaCl and Solution B is 0.60 M glucose. During the osmosis, glucose molecules flow across the semipermeable membrane to the left side of the U-shape tube.

- **D.** Initially Solution A is 0.40 M NaCl and Solution B is 0.60 M glucose. During the osmosis, more water molecules flow across the semipermeable membrane to the left side of the U-shape tube.

- **E.** Initially Solution A is 0.40 M NaCl and Solution B is 0.60 M glucose. During osmosis, NaCl molecules flow to the right side and glucose molecules flow to the left hand side.
Transcribed Image Text:An osmosis experiment uses aqueous solutions of 0.60 M glucose (non-electrolyte) and 0.40 M NaCl (strong electrolyte). These two solutions are placed in a U-shape tube separated by a semipermeable membrane. Initially, these two solutions have the same height (initial state) as shown in the picture below. After the osmosis process reaches equilibrium (final state in the picture), the solution on the left becomes higher than the solution on the right. **Diagrams Explanation:** 1. **Initial State Diagram:** - The U-shaped tube contains Solution A on the left and Solution B on the right. - Both solutions are at the same height. - A semipermeable membrane separates the two solutions. 2. **Final State Diagram:** - The left side (Solution A) shows a higher liquid level compared to the right side (Solution B). - The semipermeable membrane remains between the two solutions. **Question:** Which of the following statements is correct regarding this osmosis experiment? - **A.** Initially Solution A is 0.60 M glucose and Solution B 0.40 M NaCl. During the osmosis, more water molecules flow across the semipermeable membrane to the left side of the U-shape tube. - **B.** Initially Solution A is 0.60 M glucose and Solution B 0.40 M NaCl. During the osmosis, NaCl molecules flow across the semipermeable membrane to the left side of the U-shape tube. - **C.** Initially Solution A is 0.40 M NaCl and Solution B is 0.60 M glucose. During the osmosis, glucose molecules flow across the semipermeable membrane to the left side of the U-shape tube. - **D.** Initially Solution A is 0.40 M NaCl and Solution B is 0.60 M glucose. During the osmosis, more water molecules flow across the semipermeable membrane to the left side of the U-shape tube. - **E.** Initially Solution A is 0.40 M NaCl and Solution B is 0.60 M glucose. During osmosis, NaCl molecules flow to the right side and glucose molecules flow to the left hand side.
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Osmosis, the inevitable passage of water or any other solvents by a semipermeable membrane.

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