### Lab 2: Cobalt Chloride Equilibrium ExperimentIn this experiment, we will observe and analyze the equilibrium of the reaction:\[ \text{CoCl}_4^{2-} + 6 \text{H}_2\text{O} \rightleftharpoons \text{Co}(\text{H}_2\text{O})_6^{2+} + 4 \text{Cl}^- \]**Instructions:**Watch the associated video: [YouTube Link](https://www.youtube.com/watch?v=cWr3UDo-WeU)**Objective:**Explain your observations for each of the following scenarios:1. **On Addition of 1 M HCl**2. **On Addition of H\(_2\)O**3. **On Addition of Co(H\(_2\)O\(_6\))\(^{2+}\)****Questions:**- **(A)** Where will the equilibrium shift upon the addition of a particular reagent? (Write the complete equation to explain). - **(B)** What color change was observed? Explain why.**Key Considerations:**- The first test tube serves as the control.4. **Thermal Effects:** - Why does the equilibrium shift blue when the test tube is placed in warm water? Provide an explanation.5. **Cold Water Bath:** - What is the effect on the equilibrium mixture in a cold water bath? Explain your observations. Use this guide to help structure your lab report and deepen your understanding of chemical equilibria.

Since we only answer up to 3 sub-parts, we’ll answer the first 3. Please resubmit the question and specify the other subparts (up to 3) you’d like answered.In this question, a reaction at equilibrium is given : CoCl42- + 6 H2O ⇌ Co(H2O)62+ + 4 Cl-Blue Pink This question has asked : (a) determination of equilibrium shifts on addition of particular given reagent . (b) determination of color change and its reason after adding reagent . The equilibrium law : It is also known as Le - Chatelier's principle which states that if the equilibrium is disturbed by changing the conditions in a dynamic equilibrium then the reaction establishes a new equilibrium .Addition of 1 M HCl : On adding 1 M HCl in the given equilibrium reaction mixture, then the concentration of Cl- in the solution increases which causes the concentration of reactant increases which results in the reaction equilibrium shifts to the right direction. The color of the solution becomes blue due to increase in the concentration of reactant in the mixture.Addition of H2O : On adding H2O in the given equilibrium reaction mixture, then the concentration of H2O in the solution increases which causes the concentration of reactant increases which results in the reaction equilibrium shifts to the right direction. The color of the solution becomes blue due to increase in the concentration of reactant in the mixture.Addition of Co(H2O)62+ : On adding Co(H2O)62+ in the given equilibrium reaction mixture, then the concentration of Co(H2O)62+ in the solution increases which causes the concentration of product increases which results in the reaction equilibrium shifts to the left direction. The color of the solution becomes pink due to increase in the concentration of product in the mixture.(1) On addition of 1 M HCl : Equilibrium shifts to right direction Color obtained - blue due to increase in the concentration of reactant in the mixture. (2) On addition of H2O : Equilibrium shifts to right direction Color obtained - blue due to increase in the concentration of reactant in the mixture. (3) On addition of Co(H2O)62+ Equilibrium shifts to the right direction Color obtained - pink due to increase in the concentration of product in the mixture.

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Chemistry

Observe the equilibrium СОC/42- + 6H20 Co(H2O)62+ + 4 Cl- Explain for each_of the questions given below the following (A)Where will the equilibrium shift on addition of the particular reagent? (Write complete equation to explain). (B)What color change was observed and explain why. (Remember: The first test tube is the control). 1. On Addition of 1 M HCI 2. On Addition of H2O 3. On Addition of Co(H2O6) 2+ 4. Why did the equilibrium turn blue on putting the test tube in warm water? Explain 5. What happens when you put the equilibrium mixture in cold water bath? Explain.

Observe the equilibrium СОC/42- + 6H20 Co(H2O)62+ + 4 Cl- Explain for each_of the questions given below the following (A)Where will the equilibrium shift on addition of the particular reagent? (Write complete equation to explain). (B)What color change was observed and explain why. (Remember: The first test tube is the control). 1. On Addition of 1 M HCI 2. On Addition of H2O 3. On Addition of Co(H2O6) 2+ 4. Why did the equilibrium turn blue on putting the test tube in warm water? Explain 5. What happens when you put the equilibrium mixture in cold water bath? Explain.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

### Lab 2: Cobalt Chloride Equilibrium Experiment

In this experiment, we will observe and analyze the equilibrium of the reaction:

\[ \text{CoCl}_4^{2-} + 6 \text{H}_2\text{O} \rightleftharpoons \text{Co}(\text{H}_2\text{O})_6^{2+} + 4 \text{Cl}^- \]

**Instructions:**

Watch the associated video: [YouTube Link](https://www.youtube.com/watch?v=cWr3UDo-WeU)

**Objective:**

Explain your observations for each of the following scenarios:

1. **On Addition of 1 M HCl**
2. **On Addition of H\(_2\)O**
3. **On Addition of Co(H\(_2\)O\(_6\))\(^{2+}\)**

**Questions:**

- **(A)** Where will the equilibrium shift upon the addition of a particular reagent? (Write the complete equation to explain).

- **(B)** What color change was observed? Explain why.

**Key Considerations:**

- The first test tube serves as the control.

4. **Thermal Effects:**
- Why does the equilibrium shift blue when the test tube is placed in warm water? Provide an explanation.

5. **Cold Water Bath:**
- What is the effect on the equilibrium mixture in a cold water bath? Explain your observations.

Use this guide to help structure your lab report and deepen your understanding of chemical equilibria.

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Can someone please help me with this questions.
What is the concentration of NO2 in the equilibrium reaction below. Assume that [N2O5]eq=56.4M & [O2]eq=0.122M 2N2O5(aq) ↔ 4NO2(aq) + O2(aq) Kc=89.6 Group of answer choices A) 6.88M B) 39.1M C) 14.2M D) 7.68x10−2M
Give detailed Solution with explanation needed of each options...don't give Handwritten answer
9:14 Question 8 of 32 Draw the product of this reaction. Ignore inorganic byproducts. Br2 (2 equiv) Br Br Submit Select to Edit
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