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O MLABD = 2 (m/CBD) m/CBD = ; (mZABC) O 2 (MZABD) = m/CBD MZABC = mZCBD Submit Aprun

O MLABD = 2 (m/CBD) m/CBD = ; (mZABC) O 2 (MZABD) = m/CBD MZABC = mZCBD Submit Aprun

Elementary Geometry For College Students, 7e
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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You are shown ZABC below whose measure is 52°. Draw an angle bisector of ZABC by clicking a dragging a ray out from the vertex at B. Click and drag to draw a ray from the yellow dot. To redraw, click and drag from the yellow dot again. MZABC = 52° MZABD = 26° m/CBD = 26° A
Transcribed Image Text:You are shown ZABC below whose measure is 52°. Draw an angle bisector of ZABC by clicking a dragging a ray out from the vertex at B. Click and drag to draw a ray from the yellow dot. To redraw, click and drag from the yellow dot again. MZABC = 52° MZABD = 26° m/CBD = 26° A
A O MZABD = 2 (m/CBD) m/CBD = ; (mZABC) O 2 (MZABD) = m/CBD MZABC = M2CBD Submit Answer
Transcribed Image Text:A O MZABD = 2 (m/CBD) m/CBD = ; (mZABC) O 2 (MZABD) = m/CBD MZABC = M2CBD Submit Answer
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