O Macmillan Learning How many molecules of NaClO are in 2.336 g of NaClO4? Show the conversions required to solve this problem and calculate the molecules of NaClO4. 2.336 g NaClO X 6.022 x 1023 molecules NaC104 amount of NaC10₁ = Answer Bank 1 mol NaClO4 122.44 g NaClO4 = ? molecules NaCIO4 1 mol NaClO4 molecules NaClO4

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**Transcription of Educational Content:**

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**Title: Calculating the Number of Molecules in a Given Mass of NaClO₄**

**Problem Statement:**

How many molecules of \( \text{NaClO}_4 \) are in 2.336 g of \( \text{NaClO}_4 \)? Show the conversions required to solve this problem and calculate the molecules of \( \text{NaClO}_4 \).

**Conversion Process:**

Given:

\[ 2.336 \, \text{g NaClO}_4 \times \left( \frac{1 \, \text{mol NaClO}_4}{122.44 \, \text{g NaClO}_4} \right) \times \left( \frac{6.022 \times 10^{23} \, \text{molecules NaClO}_4}{1 \, \text{mol NaClO}_4} \right) = \, ? \, \text{molecules NaClO}_4 \]

**Answer Bank:**

- \( 6.022 \times 10^{23} \) molecules \( \text{NaClO}_4 \)
- \( 1 \) mol \( \text{NaClO}_4 \)
- \( 122.44 \) g \( \text{NaClO}_4 \)
- \( 1 \) mol \( \text{NaClO}_4 \)

**Calculation:**

1. Use the molar mass of \( \text{NaClO}_4 \) (122.44 g/mol) to convert grams to moles.
2. Use Avogadro's number \( (6.022 \times 10^{23}) \) to convert moles to molecules.

**Final Output Space:**

Amount of \( \text{NaClO}_4 = \, \text{(Insert Calculation Result Here)} \, \text{molecules NaClO}_4 \)

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This step-by-step approach provides a clear pathway for solving the problem using dimensional analysis and standard conversion factors.
Transcribed Image Text:**Transcription of Educational Content:** --- **Title: Calculating the Number of Molecules in a Given Mass of NaClO₄** **Problem Statement:** How many molecules of \( \text{NaClO}_4 \) are in 2.336 g of \( \text{NaClO}_4 \)? Show the conversions required to solve this problem and calculate the molecules of \( \text{NaClO}_4 \). **Conversion Process:** Given: \[ 2.336 \, \text{g NaClO}_4 \times \left( \frac{1 \, \text{mol NaClO}_4}{122.44 \, \text{g NaClO}_4} \right) \times \left( \frac{6.022 \times 10^{23} \, \text{molecules NaClO}_4}{1 \, \text{mol NaClO}_4} \right) = \, ? \, \text{molecules NaClO}_4 \] **Answer Bank:** - \( 6.022 \times 10^{23} \) molecules \( \text{NaClO}_4 \) - \( 1 \) mol \( \text{NaClO}_4 \) - \( 122.44 \) g \( \text{NaClO}_4 \) - \( 1 \) mol \( \text{NaClO}_4 \) **Calculation:** 1. Use the molar mass of \( \text{NaClO}_4 \) (122.44 g/mol) to convert grams to moles. 2. Use Avogadro's number \( (6.022 \times 10^{23}) \) to convert moles to molecules. **Final Output Space:** Amount of \( \text{NaClO}_4 = \, \text{(Insert Calculation Result Here)} \, \text{molecules NaClO}_4 \) --- This step-by-step approach provides a clear pathway for solving the problem using dimensional analysis and standard conversion factors.
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