O G(s )= (1) Rost locus b1arches p.2:1 (i) BP- o (14) angle of anymplate 90, 270 KEO 『こo 270 ヒニム (d) G (5)= 135 (8+1) 45 (() Rost locun branchercy keo () Angle of asymptites P-2 3ごいち! 6 45, 135, 225, 315 315 225 5--1 ) centrud
O G(s )= (1) Rost locus b1arches p.2:1 (i) BP- o (14) angle of anymplate 90, 270 KEO 『こo 270 ヒニム (d) G (5)= 135 (8+1) 45 (() Rost locun branchercy keo () Angle of asymptites P-2 3ごいち! 6 45, 135, 225, 315 315 225 5--1 ) centrud
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Question
How to get the direction of root locus?
![と-イ
(1) Root locus blarches =p.2-2
90
(*)
B-P= o
Argle of anymptatar
K-e |ビニo
90, 270
s(s)
2コ6
ヒニノ
(a) G (s)=
K
135
45
(s+1)+
(6) Root locun branchercy
keo
) angle of asymptites
P-2
3ううこち!
6 45, 135, 125, 315
315
225
Centru d](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fcc012420-4d67-48a3-8e85-bac83b5d2ff3%2F97ce7632-561a-4f8c-8e3e-0d664e8586dc%2Fzcdpqwp_processed.jpeg&w=3840&q=75)
Transcribed Image Text:と-イ
(1) Root locus blarches =p.2-2
90
(*)
B-P= o
Argle of anymptatar
K-e |ビニo
90, 270
s(s)
2コ6
ヒニノ
(a) G (s)=
K
135
45
(s+1)+
(6) Root locun branchercy
keo
) angle of asymptites
P-2
3ううこち!
6 45, 135, 125, 315
315
225
Centru d
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