Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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![**Question 40:** Does the origin lie inside or outside the ellipse with the equation \((x - 4)^2 + 4(y - 3)^2 = 4\)?
**Explanation:** This is a mathematical problem that asks whether the point (0,0), known as the origin, falls within the boundaries of the ellipse defined by the given equation.
To determine this, substitute \(x = 0\) and \(y = 0\) into the equation and evaluate:
1. Substitute values:
\((0 - 4)^2 + 4(0 - 3)^2\)
2. Calculate each term:
- \((0 - 4)^2 = 16\)
- \(4(0 - 3)^2 = 4 \times 9 = 36\)
3. Combine the results:
\[16 + 36 = 52\]
Since 52 is greater than 4, the origin lies outside the ellipse.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe4edc99d-218f-4406-99d1-341b3c217acb%2F1a7af3e6-7e84-4452-b5b7-75a1e721f660%2F619aftp_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Question 40:** Does the origin lie inside or outside the ellipse with the equation \((x - 4)^2 + 4(y - 3)^2 = 4\)?
**Explanation:** This is a mathematical problem that asks whether the point (0,0), known as the origin, falls within the boundaries of the ellipse defined by the given equation.
To determine this, substitute \(x = 0\) and \(y = 0\) into the equation and evaluate:
1. Substitute values:
\((0 - 4)^2 + 4(0 - 3)^2\)
2. Calculate each term:
- \((0 - 4)^2 = 16\)
- \(4(0 - 3)^2 = 4 \times 9 = 36\)
3. Combine the results:
\[16 + 36 = 52\]
Since 52 is greater than 4, the origin lies outside the ellipse.
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