Adjust h, k, and t to reproduce this picture, only with your ellipse being purple instead of green. State the values of h, k, and t here. Tip: the value of f is a (7,0) nice multiple of something. (3.554,-3.116) Copy and paste your picture into the document to be submitted in D2L. (7,-14)"

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
Adjust h, k, and t to reproduce this picture, only with your ellipse being purple instead of
green.
....
State the values of h, k, and t here. Tip: the value of t is a
nice multiple of something.
...
(7,0)
-5
10
(3.551,-3.116)
Copy and paste your picture into the document to be
submitted in D2L.
-10
(7.-14)
PART 3: PARABOLAS & HYPERBOLAS
1. Create a graph of a parabola that is concave up, has a vertex at the origin, and has an axis of
symmetry y=x. Copy and paste the picture of your equation, sliders, and graph into the document to
be submitted in D2L.
2. Create a square hyperbola rotated
counterclockwise. Copy and paste the picture of your equation,
sliders, and graph into the document to be submitted in D2L.
Transcribed Image Text:Adjust h, k, and t to reproduce this picture, only with your ellipse being purple instead of green. .... State the values of h, k, and t here. Tip: the value of t is a nice multiple of something. ... (7,0) -5 10 (3.551,-3.116) Copy and paste your picture into the document to be submitted in D2L. -10 (7.-14) PART 3: PARABOLAS & HYPERBOLAS 1. Create a graph of a parabola that is concave up, has a vertex at the origin, and has an axis of symmetry y=x. Copy and paste the picture of your equation, sliders, and graph into the document to be submitted in D2L. 2. Create a square hyperbola rotated counterclockwise. Copy and paste the picture of your equation, sliders, and graph into the document to be submitted in D2L.
Expert Solution
Step 1

Note: According to Bartleby guidelines; for more than one question asked, only the first one is to be answered.

The ellipse denoted by the color green has it's vertex at 7,0 and 7,-14 and hence has its center at 7,-7.

Given that the purple ellipse has its vertex at 0,7 and at 0,-7.

Therefore the center of the purple ellipse is at 0,0.

Hence in order to get the purple ellipse the value of h must change from 7 to 0 and the value of k must change from -7 to 0.

The length of the major axisa of the purple ellipse is 7 and the length of the minor axisb of the purple ellipse is 4.

 

 

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