\o _ 0 0 1|-9 -1 6 -7/ \o _ 0 0 1-9 -1 6 -7/ -3 0 2 -2 -1 1 A-1 1 1 1 -- 2 -9 -1 6 -7

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question

I have A a matrix and the question is to find the inverse of it by replace a by 2 . 

The second picture is solving for the question but I didnot understand how 3x3 matrix becomes a 4x4 matrix , would you explain it for me please 

1 2
1 0
0 0
0 0
1 0
0 1 0
1
2 0
-2
-1|0 1
-2
-3 1
3
1
2
2
-1
0 0 0
1 0
0 1
2
2 0
-2 0
-1
2
o lo o
-1
2 0
1 0
0 0
|-2
-11-3
1
1
01 1 0
-1
2 0
1
-2
0|0 0
1
-2
-1
1
0 -2
-2 -1l-3
0 -2
2
1 0
2
-5
-2
1 0 0
-5
1
1
1 0
0 0
-2 0
1
1
2
0 1
-2 0
0– 1
-2
0 -1
1
-2
1
-2
1
1
1
2
-12
-1
-3
1
-5/
0 0
-12
-1-3
1
-5
1 0
0|
1
(1 2
0 1
(1 2
0 1
-1
-1
-2 0
-2
0 0
1
1
1
1
0| 1
2
\0 0 0
-19
1
7.
0 1-9 -1
6
0 ol -3
ol 2
0 1
(1 2 0
1 0
(1
2
-2
2
-1
1
-1
1
1
0 1
0 0
0 1
1|-9
1
1
\0 0 0
-1
0 0
1|-9
-1
6
-3 0
-2
2
-1
1
A-1 =
1
2
-9
-1
-7/
Transcribed Image Text:1 2 1 0 0 0 0 0 1 0 0 1 0 1 2 0 -2 -1|0 1 -2 -3 1 3 1 2 2 -1 0 0 0 1 0 0 1 2 2 0 -2 0 -1 2 o lo o -1 2 0 1 0 0 0 |-2 -11-3 1 1 01 1 0 -1 2 0 1 -2 0|0 0 1 -2 -1 1 0 -2 -2 -1l-3 0 -2 2 1 0 2 -5 -2 1 0 0 -5 1 1 1 0 0 0 -2 0 1 1 2 0 1 -2 0 0– 1 -2 0 -1 1 -2 1 -2 1 1 1 2 -12 -1 -3 1 -5/ 0 0 -12 -1-3 1 -5 1 0 0| 1 (1 2 0 1 (1 2 0 1 -1 -1 -2 0 -2 0 0 1 1 1 1 0| 1 2 \0 0 0 -19 1 7. 0 1-9 -1 6 0 ol -3 ol 2 0 1 (1 2 0 1 0 (1 2 -2 2 -1 1 -1 1 1 0 1 0 0 0 1 1|-9 1 1 \0 0 0 -1 0 0 1|-9 -1 6 -3 0 -2 2 -1 1 A-1 = 1 2 -9 -1 -7/
-()
1
2 0
A =
а
0 -1 2
Transcribed Image Text:-() 1 2 0 A = а 0 -1 2
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