\o _ 0 0 1|-9 -1 6 -7/ \o _ 0 0 1-9 -1 6 -7/ -3 0 2 -2 -1 1 A-1 1 1 1 -- 2 -9 -1 6 -7
\o _ 0 0 1|-9 -1 6 -7/ \o _ 0 0 1-9 -1 6 -7/ -3 0 2 -2 -1 1 A-1 1 1 1 -- 2 -9 -1 6 -7
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
I have A a matrix and the question is to find the inverse of it by replace a by 2 .
The second picture is solving for the question but I didnot understand how 3x3 matrix becomes a 4x4 matrix , would you explain it for me please
![1 2
1 0
0 0
0 0
1 0
0 1 0
1
2 0
-2
-1|0 1
-2
-3 1
3
1
2
2
-1
0 0 0
1 0
0 1
2
2 0
-2 0
-1
2
o lo o
-1
2 0
1 0
0 0
|-2
-11-3
1
1
01 1 0
-1
2 0
1
-2
0|0 0
1
-2
-1
1
0 -2
-2 -1l-3
0 -2
2
1 0
2
-5
-2
1 0 0
-5
1
1
1 0
0 0
-2 0
1
1
2
0 1
-2 0
0– 1
-2
0 -1
1
-2
1
-2
1
1
1
2
-12
-1
-3
1
-5/
0 0
-12
-1-3
1
-5
1 0
0|
1
(1 2
0 1
(1 2
0 1
-1
-1
-2 0
-2
0 0
1
1
1
1
0| 1
2
\0 0 0
-19
1
7.
0 1-9 -1
6
0 ol -3
ol 2
0 1
(1 2 0
1 0
(1
2
-2
2
-1
1
-1
1
1
0 1
0 0
0 1
1|-9
1
1
\0 0 0
-1
0 0
1|-9
-1
6
-3 0
-2
2
-1
1
A-1 =
1
2
-9
-1
-7/](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F359a1891-a6e6-42ff-9fa2-e97930deb46b%2F192a7179-a654-47d3-a784-1d5aa4033a1a%2Fq7snjf9_processed.png&w=3840&q=75)
Transcribed Image Text:1 2
1 0
0 0
0 0
1 0
0 1 0
1
2 0
-2
-1|0 1
-2
-3 1
3
1
2
2
-1
0 0 0
1 0
0 1
2
2 0
-2 0
-1
2
o lo o
-1
2 0
1 0
0 0
|-2
-11-3
1
1
01 1 0
-1
2 0
1
-2
0|0 0
1
-2
-1
1
0 -2
-2 -1l-3
0 -2
2
1 0
2
-5
-2
1 0 0
-5
1
1
1 0
0 0
-2 0
1
1
2
0 1
-2 0
0– 1
-2
0 -1
1
-2
1
-2
1
1
1
2
-12
-1
-3
1
-5/
0 0
-12
-1-3
1
-5
1 0
0|
1
(1 2
0 1
(1 2
0 1
-1
-1
-2 0
-2
0 0
1
1
1
1
0| 1
2
\0 0 0
-19
1
7.
0 1-9 -1
6
0 ol -3
ol 2
0 1
(1 2 0
1 0
(1
2
-2
2
-1
1
-1
1
1
0 1
0 0
0 1
1|-9
1
1
\0 0 0
-1
0 0
1|-9
-1
6
-3 0
-2
2
-1
1
A-1 =
1
2
-9
-1
-7/
![-()
1
2 0
A =
а
0 -1 2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F359a1891-a6e6-42ff-9fa2-e97930deb46b%2F192a7179-a654-47d3-a784-1d5aa4033a1a%2F21m7jbi_processed.png&w=3840&q=75)
Transcribed Image Text:-()
1
2 0
A =
а
0 -1 2
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