O: 1s 2s 2p, 2p,? (1L IL_); there are no unpaired electrons in this oxygen atom. This configuration would be an excited state, and in going to the more stable ground state (IL I I), energy would be released.
O: 1s 2s 2p, 2p,? (1L IL_); there are no unpaired electrons in this oxygen atom. This configuration would be an excited state, and in going to the more stable ground state (IL I I), energy would be released.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Number 99 and the answer book I just don't understand. In my mind, be excited electron must be coming from 2s2 or 1s2 and landing in 2p. This the the core will have unpaired electrons. Does this term about pairing of electrons only involve the valence shells?
can just a valance shells get excited and rearrange from Oxygen's normal state of only having one orbital with two electrons and change into two orbitals with two electrons and one that is empty and they call that excited?
in other words, you can have for electrons in the 2p And if you maximize the repulsions and leave one empty that is considered excited?

Transcribed Image Text:O: 1s 2s 2p, 2p,? (1L IL_); there are no unpaired electrons in this oxygen atom. This
configuration would be an excited state, and in going to the more stable ground state
(IL I I), energy would be released.

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