Numerical answer in 4 decimal places and positive values only: kN (Upward) RA MA Rg= M₂ . kN-m (ccw) kN (Upward) 10m kN-m (cw) W wwww B

Structural Analysis
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Author:KASSIMALI, Aslam.
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Chapter2: Loads On Structures
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Please answer using moment distribution method only. Use the picture as guide for formula

Given: W= 45KN/m

RA=
AMM
Numerical answer in 4 decimal places and positive values only:
MA=
Rg=
MB =
kN (Upward)
kN-m (ccw)
KN (Upward)
10m
kN-m (cw)
W
ܩܚܥܢ
Transcribed Image Text:RA= AMM Numerical answer in 4 decimal places and positive values only: MA= Rg= MB = kN (Upward) kN-m (ccw) KN (Upward) 10m kN-m (cw) W ܩܚܥܢ
Sign convention - consider clockwise rotation is positive, counterclockwise is negative.
MBA
MAR
Fixed End Moments (FEM) - moment at the wall or fixed joint
MBA
MAB
Stiffness Factor - required moment M to rotate the end A of the beam 0₁ = 1 rad.
4EI
(absolute) K =
far end fixed
3EI
K=far end hinged
M
1
M' = M, far end fixed
(relative) K ==, E is constant
L'
3EI
M
(relative) K =
Carry-Over Moment - the moment induced at the fixed end of a beam by the action of the moment
applied at the other end.
4L
- far end hinged
B
M' = 0, far end hinged
Distribution Factor, DF - the distribution factor at a joint of a member is the ratio of the bending
stiffness of the member to the sum of bending stiffness of all the members connected to the joint.
к
DF=;
ΣΚ
Note: DF = 1, for hinge or roller support
DF = 0, for fixed support
Transcribed Image Text:Sign convention - consider clockwise rotation is positive, counterclockwise is negative. MBA MAR Fixed End Moments (FEM) - moment at the wall or fixed joint MBA MAB Stiffness Factor - required moment M to rotate the end A of the beam 0₁ = 1 rad. 4EI (absolute) K = far end fixed 3EI K=far end hinged M 1 M' = M, far end fixed (relative) K ==, E is constant L' 3EI M (relative) K = Carry-Over Moment - the moment induced at the fixed end of a beam by the action of the moment applied at the other end. 4L - far end hinged B M' = 0, far end hinged Distribution Factor, DF - the distribution factor at a joint of a member is the ratio of the bending stiffness of the member to the sum of bending stiffness of all the members connected to the joint. к DF=; ΣΚ Note: DF = 1, for hinge or roller support DF = 0, for fixed support
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