nstead of using the standard definitions of addition and scalar multiplication in R, suppose hese two operations are defined as follows. (a) (x1, Y1, 21) + (x2, Y2, 2) = (xı + x2 + 1, y1 + Y2 + 1, z1 + 22 + 1) c(x, y, z) = (cx + c – 1, cy + c – 1, cz + c – 1) With these new definitions, Show that it satisfies the Axioms 5,6, and 7

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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Instead of using the standard definitions of addition and scalar multiplication in R, suppose
these two operations are defined as follows.
(a) (x1, Y1, 21) + (x2, Y2, 2) = (x1 + x2 + 1, y1 + y2 + 1, 21 + 22 +1)
c(x, y, z) = (cx +c– 1, cy + c – 1, cz + c – 1)
With these new definitions, Show that it satisfies the Axioms 5,6, and 7
Transcribed Image Text:Instead of using the standard definitions of addition and scalar multiplication in R, suppose these two operations are defined as follows. (a) (x1, Y1, 21) + (x2, Y2, 2) = (x1 + x2 + 1, y1 + y2 + 1, 21 + 22 +1) c(x, y, z) = (cx +c– 1, cy + c – 1, cz + c – 1) With these new definitions, Show that it satisfies the Axioms 5,6, and 7
1. the set V is closed under vector addition, that is , x+y € V
2. The set V is closed under scalar multiplication, That is c1 ·x € V
3. Vector addition is commutative, that is x +y = y + x
4. vector addition is associative, that is (x+y) +z = x + (y+ z)
5. There is a zero vector 0 E V such that x + 0 = x for all x € V
%3D
6. For each x there is a unique vetro -x such that x +(-x) = 0
7. (ci + c2) ·x= cịx+ C2X
8. c1 · (x+ y) = c1 · x + c1 · y
9. (c1c2) · x = c1:)c2 · x)
10. 1·x = X
Transcribed Image Text:1. the set V is closed under vector addition, that is , x+y € V 2. The set V is closed under scalar multiplication, That is c1 ·x € V 3. Vector addition is commutative, that is x +y = y + x 4. vector addition is associative, that is (x+y) +z = x + (y+ z) 5. There is a zero vector 0 E V such that x + 0 = x for all x € V %3D 6. For each x there is a unique vetro -x such that x +(-x) = 0 7. (ci + c2) ·x= cịx+ C2X 8. c1 · (x+ y) = c1 · x + c1 · y 9. (c1c2) · x = c1:)c2 · x) 10. 1·x = X
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