ns are a = 4.0 m and b = D

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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I keep getting stuck on the moment diagram for this problem. How do I solve it?

For the beam shown, the magnitude of the concentrated load is \( P = 29 \, \text{kN} \), the magnitude of the couple is \( M_B = 240 \, \text{kN} \cdot \text{m} \), and the beam lengths are \( a = 4.0 \, \text{m} \) and \( b = 12.0 \, \text{m} \).

(a) Derive equations for the shear force \( V \) and the bending moment \( M \) for any location in the beam. Place the origin at point \( A \).  
(b) Use the derived functions to plot the shear-force and bending-moment diagrams for the beam. Use your diagrams to determine the maximum magnitude of the shear force and the maximum magnitude of the bending moment.

**Diagram Explanation:**  
The diagram shows a horizontal beam with a point \( A \) at the left end and a point \( B \) in the middle. A point \( C \) is located at the right end where the beam connects to a fixed support. A concentrated load \( P \) is applied downward at point \( A \). A moment \( M_B \) is applied as a couple at point \( B \) in a counterclockwise direction. The distance from \( A \) to \( B \) is \( a = 4.0 \, \text{m} \) and from \( B \) to \( C \) is \( b = 12.0 \, \text{m} \).

**Answer:**  
\( V_{\text{max}} = 29 \, \text{kN} \)  
\( M_{\text{max}} = -124 \, \text{kN} \cdot \text{m} \)
Transcribed Image Text:For the beam shown, the magnitude of the concentrated load is \( P = 29 \, \text{kN} \), the magnitude of the couple is \( M_B = 240 \, \text{kN} \cdot \text{m} \), and the beam lengths are \( a = 4.0 \, \text{m} \) and \( b = 12.0 \, \text{m} \). (a) Derive equations for the shear force \( V \) and the bending moment \( M \) for any location in the beam. Place the origin at point \( A \). (b) Use the derived functions to plot the shear-force and bending-moment diagrams for the beam. Use your diagrams to determine the maximum magnitude of the shear force and the maximum magnitude of the bending moment. **Diagram Explanation:** The diagram shows a horizontal beam with a point \( A \) at the left end and a point \( B \) in the middle. A point \( C \) is located at the right end where the beam connects to a fixed support. A concentrated load \( P \) is applied downward at point \( A \). A moment \( M_B \) is applied as a couple at point \( B \) in a counterclockwise direction. The distance from \( A \) to \( B \) is \( a = 4.0 \, \text{m} \) and from \( B \) to \( C \) is \( b = 12.0 \, \text{m} \). **Answer:** \( V_{\text{max}} = 29 \, \text{kN} \) \( M_{\text{max}} = -124 \, \text{kN} \cdot \text{m} \)
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