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nows, one person hits the water 5.00 m from the end of the slide in a time of 0.500 after leaving the slide. Ignoring friction and air resistance, a) Find the horizontal velocity of the swimmer at the bottom of the slide above the water." .5 5 10 m/s 6 sys vis² 29 5m b) Using kinematics equation, find the height of the bottom of the slide above the water 0. v₁₂²-29 by sys 5.0768 m Find the height H in the drawing. 155 100 2 (9-81) 6₂ (H-b) 2 h -5.00 m

nows, one person hits the water 5.00 m from the end of the slide in a time of 0.500 after leaving the slide. Ignoring friction and air resistance, a) Find the horizontal velocity of the swimmer at the bottom of the slide above the water." .5 5 10 m/s 6 sys vis² 29 5m b) Using kinematics equation, find the height of the bottom of the slide above the water 0. v₁₂²-29 by sys 5.0768 m Find the height H in the drawing. 155 100 2 (9-81) 6₂ (H-b) 2 h -5.00 m

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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18 Conservation of Mechanical Energy 200 A water slide is constructed so that swimmers, starting from rest at the top of the slide, leave the end of the slide traveling horizontally. As the drawing shows, one person hits the water 5.00 m from the end of the slide in a time of 0.500 s after leaving the slide. Ignoring friction and air resistance, a) Find the horizontal velocity of the swimmer at the bottom of the slide above the water." 15 s 10 m/s/ N sys vis 29 c) Find the height H in the drawing. Using kinematics equation, find the height of the bottom of the slide above the water 0 v₂²-29 by $5.076% m "1 g (H +h) // √ ₁ ² T 5m 15s . - 29 1 mght + mighty,² xg (H-h) - thigh & ²2 -h th * 100 sys 2 (9-81) 10.197 Water slide m H 2h 2 -5.00 m- mgl - mgh = / m M
Transcribed Image Text:18 Conservation of Mechanical Energy 200 A water slide is constructed so that swimmers, starting from rest at the top of the slide, leave the end of the slide traveling horizontally. As the drawing shows, one person hits the water 5.00 m from the end of the slide in a time of 0.500 s after leaving the slide. Ignoring friction and air resistance, a) Find the horizontal velocity of the swimmer at the bottom of the slide above the water." 15 s 10 m/s/ N sys vis 29 c) Find the height H in the drawing. Using kinematics equation, find the height of the bottom of the slide above the water 0 v₂²-29 by $5.076% m "1 g (H +h) // √ ₁ ² T 5m 15s . - 29 1 mght + mighty,² xg (H-h) - thigh & ²2 -h th * 100 sys 2 (9-81) 10.197 Water slide m H 2h 2 -5.00 m- mgl - mgh = / m M
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