Now assume that the projectile is launched from a height of H= 0.33 m above the table at an angle of 56°. Its launch speed is v₁ = 1.53 m/s. Calculate the range R, i. e. horizontal distance from launch to impact. Use g = 9.81 m/s². Enter your answer in meters without the unit. projectile launcher Viy Vi 0 Vix H R
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- A ball is thrown at an initial height of 65 feet at an initial velocity of 75 feet/second at an angle of 65 degrees. Given the parametric equations yY = - - 16t + Vo · Sin(0)t + ho and x = Vo Cos(0)t. When doing calculations, carry 5 digits of accuracy, so your round off does not build up. a. What is the ball's height in 3 seconds? feet. seconds. b. When will the object hit the ground? feet. c. How far horizontally will the ball be when it hits the ground? seconds. d. When will the ball be at its maximum height? e. What is the ball's maximum height? feet. feet f. How far horizontally will the ball be when it reaches its maximum height?A ball is thrown at an initial height of 100 feet at an initial velocity of 80 feet/second at an angle of 45 degrees. Given the parametric equations y = 16t + Vo sin(0) · t + ho and r Vo cos(0)t. - When doing calculations, carry 5 digits of accuracy, so your round off does not build up. a. What is the ball's height in 1 seconds? feet. b. When will the object hit the ground? seconds. c. How far horizontally will the ball be when it hits the ground? feet. d. When will the ball be at its maximum height? seconds. e. What is the ball's maximum height? feet. feet f. How far horizontally will the ball be when it reaches its maximum height?A ball is thrown at an initial height of 50 feet at an initial velocity of 65 feet/second at an angle of 75 degrees. Given the parametric equations y - 16t2 + Vo Sin(0)t + ho and x = Vo. Cos(0)t. When doing calculations, carry 5 digits of accuracy, so your round off does not build up. a. What is the ball's height in 2 seconds? 111.57035 v o feet. b. When will the object hit the ground? 4.60298 v o seconds. c. How far horizontally will the ball be when it hits the ground? 77.43702 v o feet. d. When will the ball be at its maximum height? 1.96204 o seconds. e. What is the ball's maximum height? 4.61479 x feet. feet f. How far horizontally will the ball be when it reaches its maximum height? 77.63571 ×
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- Suppose a cannon is placed at the origin and elevated at an angle of 60 degrees. If the cannonball is fired with a muzzle velocity of 0.18 miles per second, it will follow the graph of the following function, where distances are measured in miles. √3x- 1000x^2 / 2673 How far downrange does the cannonball travel? (Round your answer to two decimal places.)A seagull flies at a velocity of 12.5 m/s relative to the air straight into the wind. vSA = 12.5 m/st = 16 mind = 5.8 km 1. If it takes the bird 16 min to travel 5.8 km relative to the Earth, what is the velocity of the wind, in meters per second, relative to the Earth? Take the direction of travel of the seagull to be positive. 2. If the bird turns around and flies with the wind, how long, in minutes, will it take to return 5.8 km?A sinx is the mathematical model for the hypothesis given for the time of flight of a projectile as a function of angle. A: the fit parameter A...A = 2V0 B: the fit parameter B...B = B was not used in the model make a plot of the time of flight for a projectile as a function of launching angle, with v0 = 3.92 m/s...which graph most match
- 1110. In Fig. P-1109, a ball thrown down the incline strikes it at a distance s 254.5 It. If the ball rises to a maximum height h 64.4 ft above the point of release, compute its initial velocity vo and inclination 6. Ans. v. = 80.5 ft per see; 0= 53.1° FIG. P-1109 and P-1110.A particle is projected at an angle of 60 degree and a velocity of 70 m/s and taking gravity as 10m/s^2? a. Compute the maximum height of a particle. b. find the equation of trajectory. c. fnd the height of the particle when the horizontal distance is 70 m. h. Find the horizontal distance distance when the height of the particle is 100m.A cannonball is shot with an initial speed of 66 m/s and 37.0º angle with respect to the ground. How long does it take for the ball to reach its the maximum height, in seconds? Use g = 10.0 m/s2. Your answer needs to have 2 significant figures, including the negative sign in your answer if needed. Do not include the positive sign if the answer is positive. No unit is needed in your answer, it is already given in the question statement.