NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. Air enters a nozzle steadily at 50 psia, 140°F, and 150 ft/s and leaves at 14.7 psia and 900 ft/s. The heat loss from the nozzle is estimated to be 6.5 Btu/lbm of air flowing. The inlet area of the nozzle is 0.09 ft2. The enthalpy of air at the inlet is h₁ = 143.47 Btu/lbm. Determine the exit area of the nozzle. The exit area of the nozzle is 9 ft²

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part.
Air enters a nozzle steadily at 50 psia, 140°F, and 150 ft/s and leaves at 14.7 psia and 900 ft/s. The heat loss from the
nozzle is estimated to be 6.5 Btu/lbm of air flowing. The inlet area of the nozzle is 0.09 ft2. The enthalpy of air at the inlet
is h₁ = 143.47 Btu/lbm.
Determine the exit area of the nozzle.
The exit area of the nozzle is
0ft².
Transcribed Image Text:NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. Air enters a nozzle steadily at 50 psia, 140°F, and 150 ft/s and leaves at 14.7 psia and 900 ft/s. The heat loss from the nozzle is estimated to be 6.5 Btu/lbm of air flowing. The inlet area of the nozzle is 0.09 ft2. The enthalpy of air at the inlet is h₁ = 143.47 Btu/lbm. Determine the exit area of the nozzle. The exit area of the nozzle is 0ft².
Expert Solution
Step 1: Determine the given data

At space entry minus
straight P subscript 1 equals 50 space psia
straight T subscript 1 equals 140 straight F presuperscript 0
V subscript 1 equals 150 space ft divided by straight s
At space exit minus
straight P subscript 2 equals 14.7 space psia
V subscript 2 equals 900 space ft divided by straight s
Heat space loss comma straight Q subscript straight L equals 6.5 space Btu divided by lbm
Initial space area comma straight A subscript 1 equals 0.09 space ft squared
straight h subscript 1 equals 147.47 space Btu divided by lbm
To space determine colon
The space exit space nozzle space area

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