Note: The notation from this problem is from Understanding Cryptography by Paar and Pelzl.We conduct a known-plaintext attack against an LFSR. Through trial and error we have determinedthat the number of states is m = 4.The plaintext given by01110010 = 0X1X2X3X4X5X6X7when encrypted by the LFSR produced the ciphertext11000011 = YOY1Y2Y3Y3Y5Y6Y7-What are the tap bits of the LFSR? Please enter your answer as unspaced binary digits (e.g. 0101 torepresent p3 = 0, p2 = 1, p1 = 0, po = 1).

Answered: Image /qna-images/answer/9979e61a-f4e8-4950-ac33-8d1469b33214.jpg

Answered: Note: The notation from this problem is…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Suppose that Alice and Bob agree to hash an integer by taking the sum of the digits modulo 1212. Also suppose Alice has a public key with modulus 304891304891 and exponent 7373 and Bob has a private key given by the primes 619619 and 799799 with exponent 2323. Give the ciphertext Bob would send to sign the message 6005460054.
Consider a homophonic cipher in which H(A) = {000, 001, 101, 011} and H(B) = {111, 110, 010, 100}. What is the plaintext that results from the decryption of 110000100011? Answer:
Note: The notation from this problem is from Understanding Cryptography by Paar and Pelzl. Consider the LFSR represented by the polynomial x^4+x^3+x^2+1. What are the tap bits of the LFSR? Please enter your answer as unspaced binary digits (e.g. 010101 to represent p5=0,p4=1,p3=0,p2=1,p1=0,p0=1).
ONLY THE TAP BITS. The notation from this problem is from Understanding Cryptography by Paar and Pelzl. We conduct a known-plaintext attack against an LFSR. Through trial and error we have determined that the number of states is m=4m=4.The plaintext given by 01001011=x0x1x2x3x4x5x6x701001011=x0x1x2x3x4x5x6x7 when encrypted by the LFSR produced the ciphertext 11010110=y0y1y2y3y3y5y6y711010110=y0y1y2y3y3y5y6y7. What are the tap bits of the LFSR? Please enter your answer as unspaced binary digits (e.g. 0101 to represent p3=0,p2=1,p1=0,p0=1p3=0,p2=1,p1=0,p0=1).
Suppose a plaintext message x is encrypted using the Caesar cipher b = a +26 10 where each letter of the alphabet is assigned a numerical value (A = 0, B = 1, C = 2, ..., Z = 25), the variable a represents the numerical value of a letter in x, and b represents the numerical value of the corresponding letter in the ciphertext message y. If y = WKDR SC MYYV, then decrypt y to obtain the plaintext message x. Enter the decryption of each letter of y in the boxes below. NOTE: All answers should be capitalized and do not insert extra blank spaces. W → K →→ D→ R→ S→ C → M→ Y → Y → RemakingMIN... V →
Fast and correct solution please.
Suppose your RSA public key is PK: {n, e} = {13861, 37}. Your friend sends you a ciphertext C = 9908. But unfortunately you have forgotten your private key, now you have to crack it yourself.a) Write down a possible condition of factors p and q.p= q=b) What is your private key SK: {d}?d=c) What is the plaintext of your friend’s message?The plaintext M =d) Suppose the plaintext M is a 12-digit number consisting of a prefix “19” and 1234567890. What is the corresponding ciphertext? Since M is greater than n, you only need to encrypt four digits at a time. Ignore redundant zeros. e.g., 0001 = 1. The result should contain three integers.The ciphertext C0 =
Consider the case of Alice sending a message, m, to Bob. Both Alice and Bob use public key cryptography and each has a public and private key as described in the text. The figure attached below shows the operations that Alice must perform to provide confidentiality, authentication, and integrity when sending a message to Bob over the network. We can use either symmetric key or public key cryptography to encrypt a message. For our purposes, either technique will encrypt the message, and applying both doesn't make it "more secure". Also, we can assume that the session key would remain a secret so the fact that it is discarded does not make it "more secure". Why do we use a session key, Ks, instead of relying only on public key Cryptography? In other words, why do we use both public key and symmetric key cryptography?
Describe how each operating system function helps to provide a stable environment for user application execution.a. User Interface b. Error Detection c. Process Communication
A good block cipher has a 64-bit block size and uses 50-bit keys. How can we convert that in to a strong block cipher with brute force strength of 2^150?
Suppose a public-key cryptosystem encrypts integers (say, modulo another integer n). Show that if this scheme has the property that Dec(Enc(x) · Enc(y)) = x + y for any messages x, y, then the scheme is necessarily vulnerable to a CCA2 attack.
Decrypt the message MAXLJGTEAX which was encrypted using the affine cipher: f(p) = (5p + 6) mod 26 Alphabet: A = 0, B = 1, ... , Z = 25 Message:

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