Note: please solve for E and F. I have already solve for b,c,and d. This is where I am stuck at. A beam resting on two pivots has a length of L = 6.00 m and mass M = 88.0 kg. The pivot under the left end exerts a normal force n1 on the beam, and the second pivot placed a distance ℓ = 4.00 m from the left end exerts a normal force n2.
Rotational Equilibrium And Rotational Dynamics
In physics, the state of balance between the forces and the dynamics of motion is called the equilibrium state. The balance between various forces acting on a system in a rotational motion is called rotational equilibrium or rotational dynamics.
Equilibrium of Forces
The tension created on one body during push or pull is known as force.
Note: please solve for E and F. I have already solve for b,c,and d. This is where I am stuck at.
A beam resting on two pivots has a length of L = 6.00 m and mass M = 88.0 kg. The pivot under the left end exerts a normal force n1 on the beam, and the second pivot placed a distance ℓ = 4.00 m from the left end exerts a normal force n2.
A woman of mass m = 61.0 kg steps onto the left end of the beam and begins walking to the right as in the figure below. The goal is to find the woman's position when the beam begins to tip.
(b) Where is the woman when the normal force n1 is the greatest?
x = 0 0 m
(c) What is n1 when the beam is about to tip?
0 N
(d) Use the force equation of equilibrium to find the value of n2 when the beam is about to tip.
1460 N
(e) Using the result of part (c) and the torque equilibrium equation, with torques computed around the second pivot point, find the woman's position when the beam is about to tip.
x=_____________________
(f) Check the answer to part (e) by computing torques around the first pivot point.
x=________________
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