Note: Give me all three subparts right solutions A 4 m wide concrete rectangular channel with bed slope of 0.0004 has a steady discharge of 5 m3 /s. The mannings roughness constant (n) is 0.012. a) Determine the normal depth of flow using Newton Raphson method. Use initial trial depth as 0.8 m(only two iterations are required). b) Determine critical depth of flow. c) Classify the channel

Q: A circular culvert of 1.532 m diameter, flow Q = 2.32 m3 / s, depth 1 m and n = 0.014, calculate the…

A: Discharge (Q) = 2.32 m3/sDiameter of culvert (d) = 1.532 mDepth of water (y) = 1 m n = 0.014To…

Q: An open channel of trapezoidal cross section, 2.5m at the base and sides inclined at 60° to the…

A: Given: The base width is 2.5 m. The side angle is 60o. The bed slope is 1 in 500. The flow rate is…

Q: a rectangular concrete channel, the equilibrium depth is 3.2 m. The channel is 2 m wide and the bed…

A: Gievn data,y = Uniform equilibrium flow depth =3.2 mb = Channel width = 2 mS = Bed slope = 0.0006n =…

Q: A rectangular channel of bed width 25.0 m has a normal depth of 1.25 m. If Manning's coefficient n =…

A: Width of Channel B = 25m Normal Depth y = 1.25m Manning' s Coefficient  n = 0.015   (Due to Channel…

Q: can you please help me solve the homework problem. I need a step by step solution i am very confused…

A: Given data in question Width 2.96 mDepth 4.11 mSlope 0.074Constant 0.015To find out Discharge

Q: The smooth-steel channel as in the figure is designed without the barrier for a flow rate of 11…

A:

Q: A rectangular channel (b = 9 feet) crosses beneath a roadway inside a 70-inch RCP culvert with a C =…

A: Width of rectangular channel,  Diameter of Culvert,  Design Flow rate,  Standard Length of 70-in RCP…

Q: A rectangular-shaped, weedy excavated channel with width b = 30 ft is laid on a slope of 8 ft/mile.…

A:

Q: .Hydraulic jump occurs in a 4 m wide rectangular channel. Discharge in channel 7.5 m^3 /s, hydraulic…

A: Given data: Width of the channel (b) = 4m Discharge through the channel (Q) = 7.5 m3/s Depth of…

Q: A triangular section has a side slope of s = 2, Manning's n = 0.02, Bottom slope of S0 = 0.005,…

A: (1) It is required to determine the top width of the triangular channel. T=2sy=2×2×2=8 m It is…

Q: Design a straight trapezoidal erodible channel that can carry a discharge of 12.5m^3/s using…

A: Solution: Given: Mannings constant, n = 0.024 slope   so = 0.0015 Q=12 m3/s

Q: 1. Dikes are to be installed on both channel banks of the 1.2 km long river section. The river width…

A: length of river -1.2 km Width of river - 60 m Angle - 10 degrees To determine- numbers of dikes…

Q: hydraulics *use handwritten    A rectangular channel 5.50 m wide and 1.30 m deep is laid on a…

A:

Q: (a) Complete the table below for the three slope and flow classifications: Relationship between…

A: TypeRelationship between Normal depth (dn) and Critical depth (dc)Type of slopeType of…

Q: The Manning equation for a rectangular open channel can be expressed as follow, √S (BH) 5/3 n (B +…

A:

Open Channel Flow

Open channel flow is a branch of fluid mechanics. It deals with the flow of fluid in an open conduit or free surface. In an open channel flow, gravity induces the flow of water whose surface is open to the air. This flow is free-falling rather than confined in rigid body conduits. The open channel flow depends upon two parameters that are the cross-section of the conduit and the velocity profile. Practical examples of open channel flow are streams, rivers, canals, and other drainage systems.In open channel flow, the cross-sectional area of at least one of the sides is exposed to air, and the surface of water faces atmospheric pressure. This flow is also known as free gravity flow. The cross-sectional area of the conduit can be either man-made or a natural channel. For instance, the flow in rivers and streams are natural conduits, and the flow in a canal and sanitary systems are man-made or engineered channels.