Non-Steady-State Diffusion What is the value of erf(0.527) ? Value is between two data points Erf(z) 0.5633 University of Strathclyde Engineering Z erf(z) z erf(z) ? 0 0 0.55 0.5633 0.025 0.0282 0.60 0.6039 0.5205 0.05 0.0564 0.65 0.6420 0.10 0.1125 0.70 0.6778 0.15 0.1680 0.75 0.7112 0.50 0.55 0.20 0.2227 0.80 0.7421 0.527 Z 0.25 0.2763 0.85 0.7707 0.30 0.3286 0.90 0.7970 (0.527 0.50 0.35 0.3794 0.95 0.8209 erf(z) = 0.5205+ (0.5633 -0.5205) == 0.55 -0.50 0.40 0.4284 1.0 0.8427 0.45 0.4755 1.1 0.8802 0.50 0.5205 1.2 0.9103 erf(0.527) 0.5436 = Non-Steady-State Diffusion University of Strathclyde Engineering Cx-Co x 1-erf Cs-Co 2√Dt Cx-0 = 1 erf 0.1-0 (25 0.001 Cx 0.1 2√2.5 x 10-11 x 36000, - = 1 − erf(0.527) What is the value of erf(0.527) ? Co position, x Co zero (pure iron) C₁ = 0.1 x 1mm = 0.001m D = 2.5 x 10-11 m²/s t = 10 hours = 36000s

Non-Steady-State Diffusion What is the value of erf(0.527) ? Value is between two data points Erf(z) 0.5633 University of Strathclyde Engineering Z erf(z) z erf(z) ? 0 0 0.55 0.5633 0.025 0.0282 0.60 0.6039 0.5205 0.05 0.0564 0.65 0.6420 0.10 0.1125 0.70 0.6778 0.15 0.1680 0.75 0.7112 0.50 0.55 0.20 0.2227 0.80 0.7421 0.527 Z 0.25 0.2763 0.85 0.7707 0.30 0.3286 0.90 0.7970 (0.527 0.50 0.35 0.3794 0.95 0.8209 erf(z) = 0.5205+ (0.5633 -0.5205) == 0.55 -0.50 0.40 0.4284 1.0 0.8427 0.45 0.4755 1.1 0.8802 0.50 0.5205 1.2 0.9103 erf(0.527) 0.5436 = Non-Steady-State Diffusion University of Strathclyde Engineering Cx-Co x 1-erf Cs-Co 2√Dt Cx-0 = 1 erf 0.1-0 (25 0.001 Cx 0.1 2√2.5 x 10-11 x 36000, - = 1 − erf(0.527) What is the value of erf(0.527) ? Co position, x Co zero (pure iron) C₁ = 0.1 x 1mm = 0.001m D = 2.5 x 10-11 m²/s t = 10 hours = 36000s

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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