NOBr(g) decomposes to form NO and Br2 by the reaction 2 NOBr(g) + 2 NO(g) + Br2(8) It is found that the reaction is second order in NOBr. The rate constant has been found to be 0.170 M-1 s1. In a situation where the initial concentration of NOBr in a vessel is 0.690 M, how long will it take for the concentration of Br2 to reach 0.180 M? (Assume, of course, that there was no Br in the vessel to begin with.) Report your result in seconds with one decimal place but do not put units in the

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