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No. Load Elongation L. P(KN) SL(mm) W. (mm) Area Ở eng (KN/m²) E eng (mm) m2 1 100 36.1 38 0.02 100 36.1 3 76.2 0.12 100 36.1 4 92.7 0.25 100 36.1 107 0.50 100 36.1 6. 149 2.03 100 36.1 7 160.6 3.55 100 36.1 8 102 3.87 100 36.1 9 100.7 4.01 100 36.1 10 98.33 4.12 100 36.1 11 155 4.65 100 36.1 12 142 5.1 100 36.1 13 124.2 5.84 100 36.1

No. Load Elongation L. P(KN) SL(mm) W. (mm) Area Ở eng (KN/m²) E eng (mm) m2 1 100 36.1 38 0.02 100 36.1 3 76.2 0.12 100 36.1 4 92.7 0.25 100 36.1 107 0.50 100 36.1 6. 149 2.03 100 36.1 7 160.6 3.55 100 36.1 8 102 3.87 100 36.1 9 100.7 4.01 100 36.1 10 98.33 4.12 100 36.1 11 155 4.65 100 36.1 12 142 5.1 100 36.1 13 124.2 5.84 100 36.1

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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W o No. Load Elongation Lo P(KN) SL(mm) |(mm) Area O eng (KN/m²) Еeng (mm) m² 1 100 36.1 2 38 0.02 100 36.1 3 76.2 0.12 100 36.1 4 92.7 0.25 100 36.1 107 0.50 100 36.1 6. 149 2.03 100 36.1 7 160.6 3.55 100 36.1 8 102 3.87 100 36.1 9 100.7 4.01 100 36.1 10 98.33 4.12 100 36.1 11 155 4.65 100 36.1 12 142 5.1 100 36.1 13 124.2 5.84 100 36.1
Transcribed Image Text:W o No. Load Elongation Lo P(KN) SL(mm) |(mm) Area O eng (KN/m²) Еeng (mm) m² 1 100 36.1 2 38 0.02 100 36.1 3 76.2 0.12 100 36.1 4 92.7 0.25 100 36.1 107 0.50 100 36.1 6. 149 2.03 100 36.1 7 160.6 3.55 100 36.1 8 102 3.87 100 36.1 9 100.7 4.01 100 36.1 10 98.33 4.12 100 36.1 11 155 4.65 100 36.1 12 142 5.1 100 36.1 13 124.2 5.84 100 36.1
The used equations in this experiment was N/m? A SL € = diamention less зм of = 2tc2 N/m? of EB = N/m2 ef 2tc3 3 N 0: stress m2 F:applied force A = area of sample m2 SL = the chainge in length after deformation %3D m L = the initial length m N of = fracuture stress m2 M = moment of material(moment of bending) t = thickness of sample m c = half width of sample m EB = modulus of blastic ef = fracture strain %3D I = moment of inertia
Transcribed Image Text:The used equations in this experiment was N/m? A SL € = diamention less зм of = 2tc2 N/m? of EB = N/m2 ef 2tc3 3 N 0: stress m2 F:applied force A = area of sample m2 SL = the chainge in length after deformation %3D m L = the initial length m N of = fracuture stress m2 M = moment of material(moment of bending) t = thickness of sample m c = half width of sample m EB = modulus of blastic ef = fracture strain %3D I = moment of inertia
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