No calculators. Using the Disc or Washer method only, find the exact value of the volume of the solid obtained by rotating the region enclosed by y=x² and x = y² about y=1.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Question
### Calculus Problem Set

#### Problem (a)
**Task:**
Sketch the two curves on the same graph, and shade in the region between them. Show calculations for intersection points.

**Instructions:**
1. Identify the two curves you need to sketch.
2. Plot these curves on a coordinate plane.
3. Determine the points of intersection by solving the equations of the curves simultaneously.
4. Shade the region that lies between the two curves.

_Example (Not actual representation of the problem curves):_
For instance, if you're given \( y = x^2 \) and \( y = 2x + 3 \), you solve:
\[ x^2 = 2x + 3 \rightarrow x^2 - 2x - 3 = 0 \]

Factoring:
\[ (x - 3)(x + 1) = 0 \]
Thus, \( x = 3 \) and \( x = -1 \), so the intersection points are \((-1, 1)\) and \((3, 9)\).

_Sketch:_
1. Draw the parabolic curve \( y = x^2 \).
2. Draw the linear curve \( y = 2x + 3 \).
3. Shade the area between these two curves from \( x = -1 \) to \( x = 3 \).

#### Problem (b)
**Task:**
Sketch the 3D volume that results when you rotate the shaded area from part (a) about \( y = 1 \). Draw a typical disc or washer on this 3D sketch.

**Instructions:**
1. Use the shaded area derived from part (a).
2. Imagine rotating this area around the line \( y = 1 \).
3. Sketch the resulting 3D shape, typically a solid of revolution.
4. Highlight and label a typical disc or washer within the 3D sketch to indicate the individual elements used to compute the volume.

_Sketch:_
- The shape of the solid depends on the specific curves from part (a). If \( y = x^2 \) and \( y = 2x + 3 \) are rotated around \( y = 1 \), the 3D shape will be a toroidal (doughnut-like) structure.

#### Problem (c)
**Task:**
Determine an expression for \( dV \), as shown in lecture. State which
Transcribed Image Text:### Calculus Problem Set #### Problem (a) **Task:** Sketch the two curves on the same graph, and shade in the region between them. Show calculations for intersection points. **Instructions:** 1. Identify the two curves you need to sketch. 2. Plot these curves on a coordinate plane. 3. Determine the points of intersection by solving the equations of the curves simultaneously. 4. Shade the region that lies between the two curves. _Example (Not actual representation of the problem curves):_ For instance, if you're given \( y = x^2 \) and \( y = 2x + 3 \), you solve: \[ x^2 = 2x + 3 \rightarrow x^2 - 2x - 3 = 0 \] Factoring: \[ (x - 3)(x + 1) = 0 \] Thus, \( x = 3 \) and \( x = -1 \), so the intersection points are \((-1, 1)\) and \((3, 9)\). _Sketch:_ 1. Draw the parabolic curve \( y = x^2 \). 2. Draw the linear curve \( y = 2x + 3 \). 3. Shade the area between these two curves from \( x = -1 \) to \( x = 3 \). #### Problem (b) **Task:** Sketch the 3D volume that results when you rotate the shaded area from part (a) about \( y = 1 \). Draw a typical disc or washer on this 3D sketch. **Instructions:** 1. Use the shaded area derived from part (a). 2. Imagine rotating this area around the line \( y = 1 \). 3. Sketch the resulting 3D shape, typically a solid of revolution. 4. Highlight and label a typical disc or washer within the 3D sketch to indicate the individual elements used to compute the volume. _Sketch:_ - The shape of the solid depends on the specific curves from part (a). If \( y = x^2 \) and \( y = 2x + 3 \) are rotated around \( y = 1 \), the 3D shape will be a toroidal (doughnut-like) structure. #### Problem (c) **Task:** Determine an expression for \( dV \), as shown in lecture. State which
**Problem Statement:**

**No calculators.** Using the Disc or Washer method only, find the exact value of the volume of the solid obtained by rotating the region enclosed by \( y = x^2 \) and \( x = y^2 \) about \( y = 1 \).
Transcribed Image Text:**Problem Statement:** **No calculators.** Using the Disc or Washer method only, find the exact value of the volume of the solid obtained by rotating the region enclosed by \( y = x^2 \) and \( x = y^2 \) about \( y = 1 \).
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