Nitrosyl chloride reacts to form nitrogen monoxide and chlorine, like this: NOCI(g) → NO(9)+Cl(g) Use this chemical equation to answer the questions in the table below. None. Suppose 250. mmol of NOC1 are added to an empty flask. How much NO will be in the flask at Some, but less than 250. mmol. O 250. mmol. equilibrium? More than 250. mmol. None. Suppose 110. mmol of NO and 110. mmol of Cl are added to an Some, but less than 110. mmol. empty flask. How much NO will be in the flask at equilibrium? 110. mmol. More than 110. mmol.

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Chapter1: Chemical Foundations
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Nitrosyl chloride reacts to form nitrogen monoxide and chlorine, like this:
NOCI(g) → NO(g)+Cl(g)
Use this chemical equation to answer the questions in the table below.
O None.
Suppose 250. mmol of NOC1 are
added to an empty flask. How much
NO will be in the flask at
O Some, but less than 250. mmol.
O 250. mmol.
equilibrium?
O More than 250. mmol.
None.
Suppose 110. mmol of NO and
110. mmol of Cl are added to an
Some, but less than 110. mmol.
empty flask. How much NO will be
in the flask at equilibrium?
110. mmol.
O More than 110. mmol.
Transcribed Image Text:Nitrosyl chloride reacts to form nitrogen monoxide and chlorine, like this: NOCI(g) → NO(g)+Cl(g) Use this chemical equation to answer the questions in the table below. O None. Suppose 250. mmol of NOC1 are added to an empty flask. How much NO will be in the flask at O Some, but less than 250. mmol. O 250. mmol. equilibrium? O More than 250. mmol. None. Suppose 110. mmol of NO and 110. mmol of Cl are added to an Some, but less than 110. mmol. empty flask. How much NO will be in the flask at equilibrium? 110. mmol. O More than 110. mmol.
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