Nitrogen dioxide and water react to form nitric acid and nitrogen monoxide, like this: 3 NO₂(g) + H₂O(1)→ 2 HNO3(aq) + NO(g) At a certain temperature, a chemist finds that a 4.0 L reaction vessel containing a mixture of nitrogen dioxide, water, nitric acid, and nitrogen monoxide at equilibrium has the following composition: compound amount NO₂ 18.3 g H₂O 73.9 g HNO3 5.0 g NO 14.7 g Calculate the value of the equilibrium constant K for this reaction. Round your answer to 2 significant digits. K x10
Nitrogen dioxide and water react to form nitric acid and nitrogen monoxide, like this: 3 NO₂(g) + H₂O(1)→ 2 HNO3(aq) + NO(g) At a certain temperature, a chemist finds that a 4.0 L reaction vessel containing a mixture of nitrogen dioxide, water, nitric acid, and nitrogen monoxide at equilibrium has the following composition: compound amount NO₂ 18.3 g H₂O 73.9 g HNO3 5.0 g NO 14.7 g Calculate the value of the equilibrium constant K for this reaction. Round your answer to 2 significant digits. K x10
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Equilibrium in Chemical Reactions**
In this lesson, we will explore how to determine the equilibrium constant for a chemical reaction. As an example, consider the following reaction where nitrogen dioxide and water react to form nitric acid and nitrogen monoxide:
\[ 3 \text{NO}_2(g) + \text{H}_2\text{O}(l) \rightarrow 2 \text{HNO}_3(aq) + \text{NO}(g) \]
At a certain temperature, a chemist observes a 4.0 L reaction vessel containing a mixture of these substances at equilibrium with the following composition:
| Compound | Amount |
|----------|--------|
| NO\(_2\) | 18.3 g |
| H\(_2\)O | 73.9 g |
| HNO\(_3\)| 5.0 g |
| NO | 14.7 g |
To calculate the equilibrium constant (\(K_c\)) for this reaction, follow these steps:
1. **Convert Mass to Moles**:
Calculate the number of moles for each compound using their molar mass.
- Molar mass of NO\(_2\) = 14 (N) + 2×16 (O) = 46 g/mol
- Molar mass of H\(_2\)O = 2×1 (H) + 16 (O) = 18 g/mol
- Molar mass of HNO\(_3\) = 1 (H) + 14 (N) + 3×16 (O) = 63 g/mol
- Molar mass of NO = 14 (N) + 16 (O) = 30 g/mol
2. **Calculate Concentrations (M)**:
Convert moles to molarity by dividing by the volume of the reaction vessel (4.0 L).
3. **Determine \(K_c\) Using the Equilibrium Expression**:
The equilibrium constant expression for the reaction is:
\[ K_c = \frac{[\text{HNO}_3]^2 [\text{NO}]}{[\text{NO}_2]^3 [\text{H}_2\text{O}]} \]
4. **Insert Concentrations and Solve**:
Use the concentrations computed in the previous step to find \(K_c\).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F20b515c9-5e3a-448e-90a2-ac3b562e1523%2Faf58824f-c412-4a63-98cd-578a0188e590%2F25xqht5_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Equilibrium in Chemical Reactions**
In this lesson, we will explore how to determine the equilibrium constant for a chemical reaction. As an example, consider the following reaction where nitrogen dioxide and water react to form nitric acid and nitrogen monoxide:
\[ 3 \text{NO}_2(g) + \text{H}_2\text{O}(l) \rightarrow 2 \text{HNO}_3(aq) + \text{NO}(g) \]
At a certain temperature, a chemist observes a 4.0 L reaction vessel containing a mixture of these substances at equilibrium with the following composition:
| Compound | Amount |
|----------|--------|
| NO\(_2\) | 18.3 g |
| H\(_2\)O | 73.9 g |
| HNO\(_3\)| 5.0 g |
| NO | 14.7 g |
To calculate the equilibrium constant (\(K_c\)) for this reaction, follow these steps:
1. **Convert Mass to Moles**:
Calculate the number of moles for each compound using their molar mass.
- Molar mass of NO\(_2\) = 14 (N) + 2×16 (O) = 46 g/mol
- Molar mass of H\(_2\)O = 2×1 (H) + 16 (O) = 18 g/mol
- Molar mass of HNO\(_3\) = 1 (H) + 14 (N) + 3×16 (O) = 63 g/mol
- Molar mass of NO = 14 (N) + 16 (O) = 30 g/mol
2. **Calculate Concentrations (M)**:
Convert moles to molarity by dividing by the volume of the reaction vessel (4.0 L).
3. **Determine \(K_c\) Using the Equilibrium Expression**:
The equilibrium constant expression for the reaction is:
\[ K_c = \frac{[\text{HNO}_3]^2 [\text{NO}]}{[\text{NO}_2]^3 [\text{H}_2\text{O}]} \]
4. **Insert Concentrations and Solve**:
Use the concentrations computed in the previous step to find \(K_c\).
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