Nitrogen and hydrogen react to form ammonia, like this: N₂(g) + 3H₂(g) → 2 NH3(g) Use this chemical equation to answer the questions in the table below. Suppose 60.0 mmol of N₂ and 180. mmol of H₂ are added to an empty flask. How much NH3 will be in the flask at equilibrium? Suppose 125. mmol of NH3 are added to an empty flask. How much N₂ will be in the flask at equilibrium? None. O Some, but less than 120. mmol. O 120. mmol. O More than 120. mmol. O None. O Some, but less than 62.5 mmol. O 62.5 mmol. O More than 62.5 mmol. X

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Nitrogen and hydrogen react to form ammonia, like this:
N₂(g) + 3H₂(g) →
2 NH3(g)
Use this chemical equation to answer the questions in the table below.
Suppose 60.0 mmol of N₂ and
180. mmol of H₂ are added to an
empty flask. How much NH3 will be
in the flask at equilibrium?
Suppose 125. mmol of NH3 are
added to an empty flask. How much
N₂ will be in the flask at
equilibrium?
None.
O Some, but less than 120. mmol.
O 120. mmol.
O More than 120. mmol.
O None.
O Some, but less than 62.5 mmol.
O 62.5 mmol.
O More than 62.5 mmol.
X
Transcribed Image Text:Nitrogen and hydrogen react to form ammonia, like this: N₂(g) + 3H₂(g) → 2 NH3(g) Use this chemical equation to answer the questions in the table below. Suppose 60.0 mmol of N₂ and 180. mmol of H₂ are added to an empty flask. How much NH3 will be in the flask at equilibrium? Suppose 125. mmol of NH3 are added to an empty flask. How much N₂ will be in the flask at equilibrium? None. O Some, but less than 120. mmol. O 120. mmol. O More than 120. mmol. O None. O Some, but less than 62.5 mmol. O 62.5 mmol. O More than 62.5 mmol. X
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