Nitric oxide is a highly reactive, colourless and poisonous gas. It reacts with bromine as shown in the equation below. At equilibrium, concentration values of the compounds are also given below. What is the value of the equilibrium constant Keq, for the reaction below? SHOW ALL YOUR WORK. 2 NO(g) + Br₂(g) → 2 NOBr(g) [NO] = 0.02987 mol/L [Br] = 0.0204 mol/L [NOBr] = 0.0631 mol/L
Nitric oxide is a highly reactive, colourless and poisonous gas. It reacts with bromine as shown in the equation below. At equilibrium, concentration values of the compounds are also given below. What is the value of the equilibrium constant Keq, for the reaction below? SHOW ALL YOUR WORK. 2 NO(g) + Br₂(g) → 2 NOBr(g) [NO] = 0.02987 mol/L [Br] = 0.0204 mol/L [NOBr] = 0.0631 mol/L
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 121QRT: When a mixture of hydrogen and bromine is maintained at normal atmospheric pressure and heated above...
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Answer this problem.
![Nitric oxide is a highly reactive, colourless and poisonous gas. It
reacts with bromine as shown in the equation below. At equilibrium,
concentration values of the compounds are also given below. What is
the value of the equilibrium constant Keq, for the reaction below?
SHOW ALL YOUR WORK.
2 NO(g) + Br₂(g) → 2 NOBr(g)
[NO] = 0.02987 mol/L
[Br] = 0.0204 mol/L
[NOBr] = 0.0631 mol/L](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F66a8e419-3358-41bc-b246-a47bf192da25%2F1936305b-3a43-44e3-bdee-22d80d08ce28%2F4vx3jsu_processed.png&w=3840&q=75)
Transcribed Image Text:Nitric oxide is a highly reactive, colourless and poisonous gas. It
reacts with bromine as shown in the equation below. At equilibrium,
concentration values of the compounds are also given below. What is
the value of the equilibrium constant Keq, for the reaction below?
SHOW ALL YOUR WORK.
2 NO(g) + Br₂(g) → 2 NOBr(g)
[NO] = 0.02987 mol/L
[Br] = 0.0204 mol/L
[NOBr] = 0.0631 mol/L
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