NIOM mo Given the following tabulated enthalpies of formation at 298K, find the standard enthalpy of reaction for the gas-phase combustion of acetylene at 298 K: avleteo sidatiue diiw SEE2A 2 C2H2(e) + 5 O2e) 4 CO2@ + 2 H2O HV (kJ/mol) Substance he follo CO2(2) -393.5 +227.4 0.0 O2(e) -241.8 (OH (s
NIOM mo Given the following tabulated enthalpies of formation at 298K, find the standard enthalpy of reaction for the gas-phase combustion of acetylene at 298 K: avleteo sidatiue diiw SEE2A 2 C2H2(e) + 5 O2e) 4 CO2@ + 2 H2O HV (kJ/mol) Substance he follo CO2(2) -393.5 +227.4 0.0 O2(e) -241.8 (OH (s
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![### Determining Standard Enthalpy of Reaction
#### Problem Statement:
Given the following tabulated enthalpies of formation at 298K, find the standard enthalpy of reaction for the gas-phase combustion of acetylene at 298K:
\[ 2 \text{C}_2\text{H}_2(g) + 5 \text{O}_2(g) \rightarrow 4 \text{CO}_2(g) + 2 \text{H}_2\text{O(g)} \]
#### Table of Standard Enthalpies of Formation (\(\Delta H_f^\circ\)):
| Substance | \(\Delta H\) (kJ/mol) |
|-----------|-----------------------|
| \(\text{CO}_2(g)\) | -393.5 |
| \(\text{C}_2\text{H}_2(g)\) | +227.4 |
| \(\text{O}_2(g)\) | 0.0 |
| \(\text{H}_2\text{O(g)}\) | -241.8 |
#### Explanation:
- **Substances**: The table includes the substances involved in the reaction:
- \(\text{CO}_2(g)\): Carbon dioxide (gas)
- \(\text{C}_2\text{H}_2(g)\): Acetylene (gas)
- \(\text{O}_2(g)\): Oxygen (gas)
- \(\text{H}_2\text{O(g)}\): Water (gas)
- **Enthalpies of Formation**: These values represent the change in enthalpy when one mole of a compound is formed from its elements in their standard state.
- **Calculation Goal**: Use the given data to calculate the overall enthalpy change for the entire combustion reaction of acetylene.
This calculation involves applying Hess's Law, using the formula:
\[ \Delta H_{\text{reaction}} = \sum \Delta H_f^\circ (\text{products}) - \sum \Delta H_f^\circ (\text{reactants}) \]
By plugging in the given enthalpy values from the table, you can find the standard enthalpy of the reaction.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Faa11fcfc-11f7-448e-9db2-5b5a3dd5c606%2F307a7fb8-047e-4661-a56f-3f88d5168a5d%2F4p52o9c_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Determining Standard Enthalpy of Reaction
#### Problem Statement:
Given the following tabulated enthalpies of formation at 298K, find the standard enthalpy of reaction for the gas-phase combustion of acetylene at 298K:
\[ 2 \text{C}_2\text{H}_2(g) + 5 \text{O}_2(g) \rightarrow 4 \text{CO}_2(g) + 2 \text{H}_2\text{O(g)} \]
#### Table of Standard Enthalpies of Formation (\(\Delta H_f^\circ\)):
| Substance | \(\Delta H\) (kJ/mol) |
|-----------|-----------------------|
| \(\text{CO}_2(g)\) | -393.5 |
| \(\text{C}_2\text{H}_2(g)\) | +227.4 |
| \(\text{O}_2(g)\) | 0.0 |
| \(\text{H}_2\text{O(g)}\) | -241.8 |
#### Explanation:
- **Substances**: The table includes the substances involved in the reaction:
- \(\text{CO}_2(g)\): Carbon dioxide (gas)
- \(\text{C}_2\text{H}_2(g)\): Acetylene (gas)
- \(\text{O}_2(g)\): Oxygen (gas)
- \(\text{H}_2\text{O(g)}\): Water (gas)
- **Enthalpies of Formation**: These values represent the change in enthalpy when one mole of a compound is formed from its elements in their standard state.
- **Calculation Goal**: Use the given data to calculate the overall enthalpy change for the entire combustion reaction of acetylene.
This calculation involves applying Hess's Law, using the formula:
\[ \Delta H_{\text{reaction}} = \sum \Delta H_f^\circ (\text{products}) - \sum \Delta H_f^\circ (\text{reactants}) \]
By plugging in the given enthalpy values from the table, you can find the standard enthalpy of the reaction.
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