NIOM mo Given the following tabulated enthalpies of formation at 298K, find the standard enthalpy of reaction for the gas-phase combustion of acetylene at 298 K: avleteo sidatiue diiw SEE2A 2 C2H2(e) + 5 O2e) 4 CO2@ + 2 H2O HV (kJ/mol) Substance he follo CO2(2) -393.5 +227.4 0.0 O2(e) -241.8 (OH (s

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### Determining Standard Enthalpy of Reaction

#### Problem Statement:
Given the following tabulated enthalpies of formation at 298K, find the standard enthalpy of reaction for the gas-phase combustion of acetylene at 298K:

\[ 2 \text{C}_2\text{H}_2(g) + 5 \text{O}_2(g) \rightarrow 4 \text{CO}_2(g) + 2 \text{H}_2\text{O(g)} \]

#### Table of Standard Enthalpies of Formation (\(\Delta H_f^\circ\)):

| Substance | \(\Delta H\) (kJ/mol) |
|-----------|-----------------------|
| \(\text{CO}_2(g)\)  | -393.5                |
| \(\text{C}_2\text{H}_2(g)\) | +227.4                |
| \(\text{O}_2(g)\)  | 0.0                   |
| \(\text{H}_2\text{O(g)}\) | -241.8                |

#### Explanation:
- **Substances**: The table includes the substances involved in the reaction:
  - \(\text{CO}_2(g)\): Carbon dioxide (gas)
  - \(\text{C}_2\text{H}_2(g)\): Acetylene (gas)
  - \(\text{O}_2(g)\): Oxygen (gas)
  - \(\text{H}_2\text{O(g)}\): Water (gas)
  
- **Enthalpies of Formation**: These values represent the change in enthalpy when one mole of a compound is formed from its elements in their standard state.

- **Calculation Goal**: Use the given data to calculate the overall enthalpy change for the entire combustion reaction of acetylene.

This calculation involves applying Hess's Law, using the formula:

\[ \Delta H_{\text{reaction}} = \sum \Delta H_f^\circ (\text{products}) - \sum \Delta H_f^\circ (\text{reactants}) \] 

By plugging in the given enthalpy values from the table, you can find the standard enthalpy of the reaction.
Transcribed Image Text:### Determining Standard Enthalpy of Reaction #### Problem Statement: Given the following tabulated enthalpies of formation at 298K, find the standard enthalpy of reaction for the gas-phase combustion of acetylene at 298K: \[ 2 \text{C}_2\text{H}_2(g) + 5 \text{O}_2(g) \rightarrow 4 \text{CO}_2(g) + 2 \text{H}_2\text{O(g)} \] #### Table of Standard Enthalpies of Formation (\(\Delta H_f^\circ\)): | Substance | \(\Delta H\) (kJ/mol) | |-----------|-----------------------| | \(\text{CO}_2(g)\) | -393.5 | | \(\text{C}_2\text{H}_2(g)\) | +227.4 | | \(\text{O}_2(g)\) | 0.0 | | \(\text{H}_2\text{O(g)}\) | -241.8 | #### Explanation: - **Substances**: The table includes the substances involved in the reaction: - \(\text{CO}_2(g)\): Carbon dioxide (gas) - \(\text{C}_2\text{H}_2(g)\): Acetylene (gas) - \(\text{O}_2(g)\): Oxygen (gas) - \(\text{H}_2\text{O(g)}\): Water (gas) - **Enthalpies of Formation**: These values represent the change in enthalpy when one mole of a compound is formed from its elements in their standard state. - **Calculation Goal**: Use the given data to calculate the overall enthalpy change for the entire combustion reaction of acetylene. This calculation involves applying Hess's Law, using the formula: \[ \Delta H_{\text{reaction}} = \sum \Delta H_f^\circ (\text{products}) - \sum \Delta H_f^\circ (\text{reactants}) \] By plugging in the given enthalpy values from the table, you can find the standard enthalpy of the reaction.
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