**Problem Statement:**An 80.0 g sample of a gas was heated from 25 °C to 225 °C. During this process, 346 J of work was done by the system and its internal energy increased by 8915 J. What is the specific heat of the gas?**Solution:**To find the specific heat capacity (\(c\)) of the gas, we use the formula relating heat (\(q\)), mass (\(m\)), specific heat capacity (\(c\)), and change in temperature (\(\Delta T\)):\[q = mc\Delta T\]The change in internal energy (\(\Delta U\)) relates to heat added and work done:\[\Delta U = q + W\]Where:- \(\Delta U = 8915 \, \text{J}\) (change in internal energy)- \(W = -346 \, \text{J}\) (work done by the system, negative because work is done by the gas)From the equation \(\Delta U = q + W\), solve for \(q\):\[q = \Delta U - W = 8915 \, \text{J} + 346 \, \text{J} = 9261 \, \text{J}\]Now substitute \(q\) into the specific heat formula:\[9261 \, \text{J} = 80.0 \, \text{g} \cdot c \cdot (225 - 25) \, \text{°C}\]\[9261 = 80.0 \cdot c \cdot 200\]Solve for \(c\):\[c = \frac{9261}{80.0 \cdot 200} = \frac{9261}{16000} \approx 0.579 \, \text{J/(g·°C)}\] Therefore, the specific heat capacity of the gas is approximately \(0.579 \, \text{J/(g·°C)}\).

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An 80.0 g sample of a gas was heated from 25 °C to 225 °C. During this process, 346 J of work was done by the system and its internal energy increased by 8915 J. What is the specific heat of the gas? C= I Enter numeric value J/(g C

An 80.0 g sample of a gas was heated from 25 °C to 225 °C. During this process, 346 J of work was done by the system and its internal energy increased by 8915 J. What is the specific heat of the gas? C= I Enter numeric value J/(g C

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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