NHINHS Ammonium ion + amnoonia 4 Buffer syatem ma. Making a buffen r solution with D-10M & 15.0mL aud olpMR15.0mL e canjigate. base The measure eltf the solution is 9.39. Find the Ka & pka ?

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Find the Ka and pKa using Ka = ([H3O+] [A])/[HA]

**Topic: Buffer Systems – Ammonium and Ammonia**

**Buffer System:**
\[ \text{NH}_4^+ + \text{NH}_3 \]
Ammonium + Ammonia

**Problem Statement:**
You are tasked with making a buffer solution. Use 0.10 M and 15.0 mL of acid and 0.10 M and 15.0 mL of conjugate base. The measured pH of the solution is 9.39.

**Objective:**
Find the \( K_a \) and \( pK_a \).

**Notes:**
- Understanding buffer systems is crucial for maintaining stable pH conditions in chemical and biological processes.
- The \( K_a \) value represents the acid dissociation constant, a measure of the strength of an acid in solution.
- \( pK_a \) is the logarithmic form of \( K_a \) and gives insight into the acidity; calculated as \( pK_a = -\log(K_a) \).

**Steps to Solve:**
1. Use the Henderson-Hasselbalch equation:
   \[ \text{pH} = pK_a + \log \left(\frac{[\text{Base}]}{[\text{Acid}]}\right) \]
2. Substitute the given values into the equation to find \( pK_a \) and hence \( K_a \).

Understanding how to determine \( K_a \) and \( pK_a \) is essential for calculating the acid strength and predicting chemical behavior.
Transcribed Image Text:**Topic: Buffer Systems – Ammonium and Ammonia** **Buffer System:** \[ \text{NH}_4^+ + \text{NH}_3 \] Ammonium + Ammonia **Problem Statement:** You are tasked with making a buffer solution. Use 0.10 M and 15.0 mL of acid and 0.10 M and 15.0 mL of conjugate base. The measured pH of the solution is 9.39. **Objective:** Find the \( K_a \) and \( pK_a \). **Notes:** - Understanding buffer systems is crucial for maintaining stable pH conditions in chemical and biological processes. - The \( K_a \) value represents the acid dissociation constant, a measure of the strength of an acid in solution. - \( pK_a \) is the logarithmic form of \( K_a \) and gives insight into the acidity; calculated as \( pK_a = -\log(K_a) \). **Steps to Solve:** 1. Use the Henderson-Hasselbalch equation: \[ \text{pH} = pK_a + \log \left(\frac{[\text{Base}]}{[\text{Acid}]}\right) \] 2. Substitute the given values into the equation to find \( pK_a \) and hence \( K_a \). Understanding how to determine \( K_a \) and \( pK_a \) is essential for calculating the acid strength and predicting chemical behavior.
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