NH3 (9) + 3 F2(g) NF3(g) + 3 HF(g)The fluorination of ammonia is represented by the balanced equation above. Approximate values of AG° , for the reactants and products are given in the following table.CompoundAG": (kJ/mol)NH3(9)-16F2(9)NF3(g)-91HF (g)-280Based on the information, which of the following statements best helps to explain whether or not the reaction is thermodynamically favored at 298 K?AAGn << 0 and the reaction is thermodynamically favored because the product molecules have more complex structures and greater absolute entropies than the reactant molecules do.AG",B"Tzn >> 0 and the reaction is not thermodynamically favored because the total number of moles of gas-phase products is not greater than the total number of moles of gas-phasereactants.AG" Tzn << 0 and the reaction is thermodynamically favored because the energy released when the bonds in the products are formed is greater than the energy absorbed to break thebonds in the reactants.AG"n >> 0 and the reaction is not thermodynamically favored because the energy released when the bonds in the products are formed is less than the energy absorbed to break thebonds in reactants.ScQ Search or enter website name$%&

We have given that NH3(g) + 3F2(g) → NF3(g) + 3HF(g) ∆Gf of NH3(g) = -16KJ/mole ∆Gf of…

NH3(g) + 3 F2(g) → NF3(g) + 3 HF(g) The fluorination of ammonia is represented by the balanced equation above. Approximate values of AG" , for the reactants and products are given in the following table. Compound AG" (kJ/mol) NH3(g) -16 F2(g) NF3(g) -91 HF(g) -280 Based on the information, which of the following statements best helps to explain whether or not the reaction is thermodynamically favored at 298 K? AG Ten << 0 and the reaction is thermodynamically favored because the product molecules have more complex structures and greater absolute entropies than the reactant molecules do. A AG'FEn >> 0 and the reaction is not thermodynamically favored because the total number of moles of gas-phase products is not greater than the total number of moles of gas-phase B reactants. AG"n << 0 and the reaction is thermodynamically favored because the energy released when the bonds in the products are formed is greater than the energy absorbed to break the bonds in the reactants.

NH3(g) + 3 F2(g) → NF3(g) + 3 HF(g) The fluorination of ammonia is represented by the balanced equation above. Approximate values of AG" , for the reactants and products are given in the following table. Compound AG" (kJ/mol) NH3(g) -16 F2(g) NF3(g) -91 HF(g) -280 Based on the information, which of the following statements best helps to explain whether or not the reaction is thermodynamically favored at 298 K? AG Ten << 0 and the reaction is thermodynamically favored because the product molecules have more complex structures and greater absolute entropies than the reactant molecules do. A AG'FEn >> 0 and the reaction is not thermodynamically favored because the total number of moles of gas-phase products is not greater than the total number of moles of gas-phase B reactants. AG"n << 0 and the reaction is thermodynamically favored because the energy released when the bonds in the products are formed is greater than the energy absorbed to break the bonds in the reactants.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

Consider the following balanced combustion reaction: C7H16(l) + 11 O2(g) → 7 CO2(g) + 8 H2O(g) ΔrH°= -1160 kJ/mol If the density of C7H16(l) is 0.68 g/mL, how much heat (in J and scientific notation) is released if 125 mL of C7H16(l) undergoes complete combustion?
The average molecular speed in a sample of Kr gas at a certain temperature is 298 m/s. The average molecular speed in a sample of O3 gas is m/s at the same temperature.
The following thermochemical equation is for the reaction of sodium(s) with water(1) to form sodium hydroxide(aq) and hydrogen(g). 2Na(s) + 2H2O(1)- →2NaOH(aq) +H2(g) AH= -369 kJ When 5.86 grams of sodium(s) react with excess water(1), kJ of energy are
The following thermochemical equation is for the reaction of carbon(s) with oxygen(g) to form carbon dioxide(g). C(s,graphite) + O2(g) CO2(g) AH = -394 kJ How many grams of C(s,graphite) would have to react to produce 99.7 kJ of energy? grams
The reaction below has a heat of reaction of -536 kJ. How much energy in kJ is released when 55.0g of H2 are decomposed? 2H2(g) + O2(g) —> 2H2O(g)
The following thermochemical equation is for the reaction of carbon monoxide(g) with oxygen(g) to form carbon dioxide(g). 2CO(g) + O2(g)- →2CO2(g) AH=-566 kJ How many grams of CO(g) would have to react to produce 104 kJ of energy? grams
A chemist measures the energy change AH during the following reaction: Cl₂(g) + H₂(g) → 2 HC1 (g) AH=184. kJ Use the information to answer the following questions. endothermic. This reaction is... 0 exothermic. Suppose 28.0 g of Cl₂ react. Yes, absorbed. Yes, released. Will any heat be released or absorbed? No. If you said heat will be released or absorbed in the second part of this question, calculate how much heat will be released or absorbed. Round your answer to 3 significant digits. ☐kJ x10 X ?
A 125 g piece of rock of unknown specific heat is heated to 93 degrees C. The rock is then dropped into 100 g of water at 19 degrees C. the water temperature rises to 31 degrees C. What is the specific heat of the rock? (3) O 0.65 J/(g °C) O 0.65 J O 0.71 J/g °C) O 1.14 J/g.
3. During the experiment, when calculating AH using the formula AH=C x AT, can we calculate the AH without measuring the amount of water that we put inside the calorimeter? Explain why or why not. (max of 5 sentences) 4. You accidentally forgot to measure the mass of the octane that you transferred in the crucible. You already started the calorimeter and it is too late to stop the equipment. Is it still possible to calculate the energy (in Joules) of octane? Explain.(max of 2 sentences)
4. Consider the equations for these reactions: % N2 + % O2 → NO NO2 → NO + % 02 AH = +90.4 kJ AH = +56.5 All reactants are gaseous. What is the heat of formation (AH;) for NO2 gas?
Consider the reaction of ammonia gas with O2(g) according to the thermochemical equation given below: 4NH3(g) + 7O2(g) 4NO2(g) + 6H2O(1) AH° = -1132 kJ/mole (c) Write the thermochemical equation representing the combustion of 1 mole of ammonia. (d) Write the thermochemical equation representing the reaction of 1 mole NO2(g) with Hz0
Consider the reaction of ammonia gas with O2(g) according to the thermochemical equation given below: 4NH3(g) + 702(g) – 4NO2(g) + 6H2O(1) AH° = - 1132 kJ/mole I (a) Calculate the mass (g) NO2 produced together with the release of 226 J of heat. (b) Calculate the heat released when 3.75 g of NO2 are produced.