nfidence interval for the population proportion is ( H D three decimal places as needed.) your results. Choose the correct answer below. he endpoints of the given confidence interval show that adults pay bills online 99% of the time. ith 99% confidence, it can be said that the sample proportion of adults who say they have started paying bills online in the last year is between the endpoints the given confidence interval. ith 99% confidence, it can be said that the population proportion of adults who say they have started paying bills online in the last year is between the ndpoints of the given confidence interval.

Q: In a survey of 3001 ​adults, 1486 say they have started paying bills online in the last year.…

A: Assuming that the number of people paying bills online has a binomial distribution with n=3001, and…

Q: In a survey of 2224 adults in a recent​ year, 1280 say they have made a New​ Year's resolution.…

A: Obtain the 90% confidence interval for the population proportion. The 90% confidence interval for…

Q: In a survey of 2865 ​adults, 1413 say they have started paying bills online in the last year.…

A:

Q: survey of 2542 adults in a recent​ year, 1362 say they have made a New​ Year's resolution.…

A: From the given information we construct 90% and 95% confidence interval.

Q: A survey of 120 female freshmen showed that 9 did not wish to work after marriage.  Find the 99%…

A:

Q: n a survey of 2558 ​adults, 1413 say they have started paying bills online in the last year.…

A: Solution: Given information: n= 2558 Sample size of adults  x = 1413 adults started paying bills…

Q: In a survey of 2549 adults in a recent​ year, 1270 say they have made a New​ Year's resolution.…

A:

Q: In a survey of 2195 adults in a recent​ year, 1454 say they have made a New​ Year's resolution.…

A:

Q: In a survey of 3254 ​adults, 1433 say they have started paying bills online in the last year.…

A: Given X=1433 n=3254

Q: In a survey of 3478 adults, 1462 say they have started paying bills online in the last year.…

A: From the provided information,Confidence level = 99%

Q: In a survey of 2703 ​adults, 1438 say they have started paying bills online in the last year.…

A: We have given that, Number of favorable cases(X) = 1438,   Sample size(n) = 2703 Sample proportion…

Q: Out of 400 people sampled, 32 had kids. Based on this, construct a 95% confidence interval for the…

A: Solution: Let X be the number of people had kids and n be the sample number of people. From the…

Q: confidence interval for the proportion of unemployed adults who have been unemployed for more than…

A: Here given  In a survey of 532 unemployed adults, 225 said that they had been unemployed for more…

Q: In a survey of 3185 adults, 1455 say they have started paying bills online in the last year.…

A:

Q: In a survey of 2405 adults in a recent​ year, 1217 say they have made a New Year's resolution.…

A: Given: n=2405 x=1217

Q: In a survey of 793 adults, 460 say they have started paying bills online in the last year. Construct…

A: Answer: From the given data, Sample size(n) = 793 X = 460 98% confidence interval,

Q: In a survey of 3285​ adults, 1424 say they have started paying bills online in the last year.…

A: X = 1424 N = 3285 99% Confidence level

Q: In a survey of 2896 adults, 1441 say they have started paying bills online in the last year.…

A: Given data X=1441 n=2896

Q: In a survey of 2552 ​adults, 1423 say they have started paying bills online in the last year.…

A: Given that, In a survey of 2552 adults, 1423 say they have started paying bills online in the last…

Q: In a survey of 26582658 ​adults, 14961496 say they have started paying bills online in the last…

A: The objective of this question is to construct a 99% confidence interval for the population…

Q: In a survey of 2407 adults in a recent​ year,1468 say they have made a New​ Year's resolution.…

A: Given that,  Sample size, n= 2407 And X= 1468 We know that proportion, p=X/n So p= 1468/2407 p=…

Q: In a survey of 589 adults, 233 say they have started paying bills online in the last year. Construct…

A:

Q: In a survey of 2108 adults in a recent​ year, 1305 say they have made a New​ Year's resolution.…

A:

Q: In a survey of 2000 adults in a recent​ year 1404, say they have made a New​ Year's resolution.…

A: n=2000x=1404

Q: A sample of 3048 randomly chosen people found that 341 of them were left-handed. Construct a 99%…

A: Sample proportion=p^=xn=3413048Critical value for 99% confidence interval is=z=2.576n=sample…

Q: a survey of 3409 adults, 1445 say they have started paying bills online in the last year.  Construct…

A: The confidence interval = 99%The faovarble cases [x] = 1445The sample size [n] = 3409

Q: In a survey of 3235 adults 1499 say they have started paying bills online in the last year. A 99%…

A: Solution: Let X be the number of adults say they have started paying bills online in the last year…

Q: In a survey of 3983 ​adults, 747 oppose allowing transgender students to use the bathrooms of the…

A:

Q: 82 adults selected randomly from one town, 66 have health insurance. Find a 90% confidence interval…

A:

Q: In a survey of 2693 ​adults, 1495 say they have started paying bills online in the last year.…

A: Given that, In a survey of 2693 ​adults, 1495 say they have started paying bills online in the last…

Q: In a survey of 2334 adults in a recent​ year,1370 say they have made a New​ Year's resolution.…

A: Given n=2334 X=1370

Q: In a survey of 3292 adults, 1470 say they have started paying bills online in the last year.…

A: Using Excel formula “=NORM.S.INV(1-(0.01/2))”, the critical value for 99% confidence level is…

Q: Out of 100 people sampled, 44 have lied to a family member in the past month. Based on this,…

A:

Q: In a survey of 3102 adults,1401 say they have started paying bills online in the last year.…

A: Obtain the 99% confidence interval for the true population proportion. The 99% confidence interval…

Q: 90% and​ 95% confidence intervals for the population proportion. Interpret the results and compare…

A: Answer Favorable cases [x] = 1230The sample size [n] = 2105

Q: Out of 157 randomly selected adults in the United States who were surveyed, 77 exercise on a regular…

A:

Q: As health insurance costs and the number of disabled employees increase, more companies are firing…

A: Confidence Interval: The form of the confidence interval is, CI = Point estimate ± Margin of error…

Q: In a survey of 3426 ​adults, 1487 say they have started paying bills online in the last year.…

A: From the provided information, Sample size (n) = 3426 Out of which 1487 say they have started paying…

Q: 980 adults to learn about their gym membership. The results showed that 574 of the respondents lack…

A: The random variable X follows normal distribution. We have to construct 95% confidence interval for…

Q: In a survey of 2417 adults in a recent​ year, 1458 say they have made a New​ Year's resolution.…

A:

Q: In a survey of 2497 adults in a recent​ year, 1383 say they have made a New​ Year's resolution.…

A: The sample size (n) is 2497 and the value of x is 1383.

Q: In a survey of 2588 ​adults, 1466 say they have started paying bills online in the last year.…

A: Construct 99% confidence interval for population proportion:The sample of 2,588 adults among that…

Q: In a survey of 2554 adults in a recent​ year, 1357 say they have made a New​ Year's resolution.…

A:

Q: An actuary is interested in estimating the proportion of young adults who plan to have children…

A: We need to construct the 99% confidence interval for the population proportion. We have been…

Q: In a survey of 3246 ​adults, 1418 say they have started paying bills online in the last year.…

A: Given information Number of adults surveyed(n) = 3246 Number of people who started paying bills…

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.