Newton's heating-cooling law states that the rate of change in the temperature, H, is proportional to the difference between the object and the surrounding temperature. LetH(t) be the temperature of the object being heated and S be the surrounding temperature. A hot cup of coffee, 170 degrees Fahrenheit, is placed in a 70 degree room. After 20 minutes the cup is 120 degrees. Write and solve the differential equation which describes the temperature of the coffee over time, where time is measured in hours. ○ H(t) = 70 + 30e¯ -2.079t ○ H(t) = 70-30e- ○ H(t) = 70 - 100e- ○ H(t) = 70 + 100e-2.079t ,-2.079t -2.079t

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Newton's heating-cooling law states that the rate of change in the temperature, H, is proportional to the difference between the object
and the surrounding temperature. LetH(t) be the temperature of the object being heated and S be the surrounding temperature. A
hot cup of coffee, 170 degrees Fahrenheit, is placed in a 70 degree room. After 20 minutes the cup is 120 degrees.
Write and solve the differential equation which describes the temperature of the coffee over time, where time is measured in hours.
OH(t) = 70 + 30e-2.079t
OH(t) = 70 - 30e-2.079t
OH(t) = 70 - 100e-2.079t
OH(t) = 70 + 100e-2.079t
Transcribed Image Text:Newton's heating-cooling law states that the rate of change in the temperature, H, is proportional to the difference between the object and the surrounding temperature. LetH(t) be the temperature of the object being heated and S be the surrounding temperature. A hot cup of coffee, 170 degrees Fahrenheit, is placed in a 70 degree room. After 20 minutes the cup is 120 degrees. Write and solve the differential equation which describes the temperature of the coffee over time, where time is measured in hours. OH(t) = 70 + 30e-2.079t OH(t) = 70 - 30e-2.079t OH(t) = 70 - 100e-2.079t OH(t) = 70 + 100e-2.079t
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