An electron with a horizontal speed of 4600000 m/s and no vertical component of velocity passes through two horizontal parallel plates, as shown. The magnitude of the electric field between the plates is 240 N/C. The plates are 6 cm long. Calculate the angle to the horizontal, 0 (in degrees), that the electron would pass through the plates with. e>>> е + + + + + + 0 y -X

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Chapter1: Units, Trigonometry. And Vectors
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An electron with a horizontal speed of 4600000 m/s and no vertical component of
velocity passes through two horizontal parallel plates, as shown. The magnitude of
the electric field between the plates is 240 N/C. The plates are 6 cm long. Calculate
the angle to the horizontal, 0 (in degrees), that the electron would pass through the
plates with.
e
+ + + + + +
YY
y
X
Transcribed Image Text:An electron with a horizontal speed of 4600000 m/s and no vertical component of velocity passes through two horizontal parallel plates, as shown. The magnitude of the electric field between the plates is 240 N/C. The plates are 6 cm long. Calculate the angle to the horizontal, 0 (in degrees), that the electron would pass through the plates with. e + + + + + + YY y X
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